The proof of this can be get with a slight modification. It can be prove that every bounded is convergent, If (an) is an increasing and bounded sequence, then limn → ∞an = sup{an:n∈N} and if (an) is a decreasing and bounded sequence, then limn→∞an = inf{an:n∈N}.
Answer:
102
Step-by-step explanation:
Since we know that the numbers are two consecutive even numbers, we can write an equation like this where n represents the 2 numbers.
n + (n+2) = 206
Simplify the left side:
n + (n+2) = 206 -----> 2n+2 = 206
Subtract 2 from both sides:
2n = 206-2 -----> 2n = 204
Now divide 204 by 2:
n = 204/2 -----> n = 102
2x + 8 would be the simplified version of this question
Answer:
its d
Step-by-step explanation:
y=-3/4+3 I think that's right
Answer:
3x-2y
Step-by-step explanation:
log10^(3x-2y)
We know the base is base 10 since it is not written
log10 10^(3x-2y)
The log10 10 cancels
3x-2y
