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avanturin [10]
3 years ago
10

Find the value of cos W rounded to the nearest hundredth, if necessary,

Mathematics
1 answer:
Aliun [14]3 years ago
4 0

Answer:

cos W = 7/15

Step-by-step explanation:

Mathematically the cosine of an angle is the ratio of the adjacent to the hypotenuse side

From the diagram given, 14 is adjacent to vertex w and 30 faces the right angle which makes it the hypotenuse

So, we have it that;

cos W = 14/30

cos W = 7/15

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I need some help with this calculus 1 question.
Cerrena [4.2K]

Answer:

(a) f'(1)=-4

(b) y+4x-4=0

Step-by-step explanation:

<u>Tangent Line of a Function</u>

Given f(x) a real differentiable function in x=a, the slope of the tangent line of the function in x=a is given by f'(x=a). Where f' is the first derivative of f.

We are given

y=x-x^5

The derivative is

y'=1-5x^4

(a) The slope of the tangent line at (1,0) is

f'(1)=1-5\cdot 1^4=-4

f'(1)=-4

(b) The equation of the tangent line can be found with the general formula of the line:

y-y_o=m(x-x_o)

Where m is the slope and the point (xo,yo) belongs to the line. We have m=-4, xo=1, yo=0, thus

y-0=-4(x-1)

Or, equivalently

y+4x-4=0

3 0
3 years ago
I need to use the Pythagorean Theorem to find X. I don’t know how to do that!!
frutty [35]

Answer:

17) x=8

18) x=\sqrt{189} or x= 3\sqrt{21}

Step-by-step explanation:

So the rule is a^{2} +b^{2} =c^{2}, "c" being the hypothenuse, or the long line that is opposite to the right angle.

17) We know that both values of x are equal to each other, which makes everything 10x easier!

                                               x^{2} +x^{2} =(8\sqrt{2})  ^{2}

(by the way we know the x values are our a and b values because they are legs! the way I like to remember the legs is that they are connected to the right angle box, and therefore support the hypothenuse)

<em>simplify</em> (╥︣﹏╥)    

                                                2x^2=8^2(\sqrt{2} )^{2}  

                                                  2x^2=64(2)

                                                   2x^2=128    

                                                  x^{2}= 128/2  

                                                     x^{2} =64

                                                        x=8      

18) Just pretend that the flipped triangle doesn't exist. It's parallel to the other triangle with values on it, and basically servers no purpose other than being parallel to the sister triangle :)

Anyways, since we know the hypothenuse (15) but we don't know one of our leg values (x), we're going to change our equation a bit!

                                                    c^{2} - b^{2} = a^{2}

It doesn't matter if you put the one leg value in a or b, just as long as you stick to that same equation you started with the entire time!

                                                   15^{2} -6^{2} =x^{2}

                                                   225-36=x^{2}  

                                                     x^{2} =189

                                               x=\sqrt{189}=3\sqrt{21}

        The more you do these, the easier they'll get, so don't worry!

                           

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Step-by-step explanation:

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Please help me, I really need help
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Answer:

23

Step-by-step explanation:

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