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vlada-n [284]
3 years ago
11

What is 10 times as much as 0.5

Mathematics
2 answers:
Luda [366]3 years ago
8 0
0.5 × 10 is equal to 5.
marishachu [46]3 years ago
6 0
10 times as much as 0.5 =5.0
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I'm not sure what's the answer
kow [346]

Answer:

m=17/40  \frac{17}{40}

Step-by-step explanation:

So you 5/7m - 1/7 = 9/56 \frac{5}{7}m - \frac{1}{7} = \frac{9}{56}

You Simplify both sides Then

well I Don´t know I hope this helped u, I tried ^^¨

8 0
3 years ago
I need help with this math question
kirill115 [55]

Answer:

Step-by-step explanation:

6 0
2 years ago
Ishaan is 222 times as old as Christopher. 353535 years ago, Ishaan was 777 times as old as Christopher.
klemol [59]
<h3><u>Question:</u></h3>

Ishaan is 2 times as old as Christopher. 35 years ago, Ishaan was 7 times as old as Christopher. How old is Christoper now?

<h3><u>Answer:</u></h3>

The present age of Christoper is 42 years old

<h3><u>Solution:</u></h3>

Given that Ishaan is 2 times as old as Christoper

Let the present age of Christoper be "x"

Then, Present age of Ishaan = 2 times as old as Christoper

present age of Ishaan = 2x

<em><u>35 years ago, Ishaan was 7 times as old as Christopher</u></em>

Age of Ishaan 35 years ago = Present age of Ishaan - 35

Age of Ishaan 35 years ago = 2x - 35

Similarly,

Age of christoper 35 years ago = Present age of christoper - 35

Age of christoper 35 years ago = x - 35

From given statement, 35 years ago, Ishaan was 7 times as old as Christopher

Age of Ishaan 35 years ago = 7 times the age of Christoper 35 years ago

(2x - 35) = 7(x - 35)

<em><u>Solve the above equation for "x"</u></em>

2x - 35 = 7x - 245

2x - 7x = -245 + 35

-5x = -210

<h3>x = 42</h3>

Thus present age of Christoper is 42 years old

5 0
3 years ago
Plz help I need it by today
neonofarm [45]

Answer:

2688x^2 + 3640x + 1225

Step-by-step explanation:

multiply the expression

5 0
3 years ago
Read 2 more answers
For each pair figures, find the ratio of the area of the first figure to the area of the second. 14mm 7mm
Paraphin [41]

The ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

<h3>Ratio of the areas of similar figures </h3>

From the question, we are to determine the ratio of the area of the<u> first figure</u> to the area of the <u>second figure</u>

<u />

The two figures are similar

From one of the theorems for similar polygons, we have that

If the scale factor of the sides of <u>two similar polygons</u> is m/n then the ratio of the areas is (m/n)²

Let the base length of the first figure be ,m = 14 mm

and the base length of the second figure be, n = 7 mm

∴ The ratio of their areas will be

(\frac{14 \ mm}{7 \ mm})^{2}

= \frac{196 \ mm^{2} }{49\ mm^{2} }

=\frac{4}{1}

= 4:1

Hence, the ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446

8 0
1 year ago
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