In ABCD, mZB = 94º and mC = 65°. Which statement about the sides of ABCD

You are assigned by columbus high school to design a playground as part of your volunteer service. the playground consists of tw

Firlakuza [10]

Answer:

sorry

okkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk

4 0

8 months ago

Specifications for a piece of material used in the manufacture of a bed mattress require that the piece be between a Lower and U

wolverine [178]

Answer:

Hello a value is missing in your question below is the value

samples of n = 10

answer : 24.63 < μ < 25.370

Step-by-step explanation:

Given :

Sample size = n = 10

Z∝/2 = Z0.0256 = 1.95

next calculate for margin of error

E = Z∝/2 * ( 0.6 / / $\sqrt{10}$ )

= 0.370

therefore at 94.87% confidence interval the estimated population mean is

x - 0.370 < μ < x + 0.370

25 - 0.370 < μ < 25 + 0.370

24.63 < μ < 25.370

4 0

2 years ago

10% of Kindergarteners know how to read before school starts. If there are 150 kindergarteners at a

Tamiku [17]

Answer:

15

Step-by-step explanation:

To get 10 percent, you divide by 10.

150 divided by 10 equals 15.

3 0

3 years ago

Read 2 more answers

Write an equation of the line shown. Then use the equation to find the value of x when y=112

PtichkaEL [24]

Answer:

$y = 8x + 16$

$x = 12$

Step-by-step explanation:

Given two points on the line (0, 16) and (3, 40), an equation for the line can be written using the slope-intercept line equation which takes the format $y = mx + b$ .

Where,

$m = slope = \frac{y_2 - y_1}{x_2 - x_1}$

b = y-intercept or the point at which the line cuts the y-axis.

Let's find slope (m) using the slope formula:

Let,

$(0, 16) = (x_1, y_1)$

$(3, 40) = (x_2, y_2)$

$slope (m) = \frac{40 - 16}{3 - 0}$

$slope (m) = \frac{24}{3}$

$slope (m) = 8$

Find b. Substitute the values of x = 0, y = 16, and m = 8 in the slope-intercept formula to find b.

$y = mx + b$

$16 = 8(0) + b$

$16 = 0 + b$

$16 = b$

$b = 16$

Plug in the values of m and b into the slope-intercept formula to get the equation of the line.

$y = mx + b$

$y = 8x + 16$

Let's use the equation to find x when y = 112.

$y = 8x + 16$

Substitute y = 112 in the equation

$112 = 8x + 16$

$112 - 16 = 8x$

$96 = 8x$

Divide both sides by 8

$12 = x$

$x = 12$

8 0

2 years ago

I need the answers for these pls help

DanielleElmas [232]

Answer:

1)

A. m arc QRS = 100°

B. m arc QRT = 255°

C. m arc UTS = 180°

D. m arc UTR = 205°

2)

1] The major arc CA = 255°

2] The minor arc AB = 90°

Step-by-step explanation:

In a circle:

The measure of an central angle is equal to the measure of its subtended arc
The measure of a circle is 360°
Any chord divides a circle into two arcs, a minor arc its measure is < 180° and a major arc its measure is > 180°, the sum of the measures of the minor and major arcs is 360°
If the measures of the minor and major arcs are equal, then each arc represents a semi-circle

1)

In circle O

A.

∵ m∠QOR = 75°

∵ ∠QOR subtended by arc QR

- By using the 1st note above

∴ m of arc QR = m∠QOR

∴ m of arc QR = 75°

∵ m∠ROS = 25°

∵ ∠ROS subtended by arc RS

∴ m of arc RS = m∠ROS

∴ m of arc RS = 25°

The measure of arc QRS is the sum of the measures of arcs QR and RS

∴ m arc QRS = 75° + 25° = 100°

B.

∵ m∠SOT = 155°

∵ ∠SOT subtended by arc ST

∴ m of arc ST = m∠SOT

∴ m of arc ST = 155°

The measure of arc QRT is the sum of the measures of arcs QR, RS and ST

∴ m arc QRT = 75° + 25° + 155 °= 255°

C.

∵ m∠UOT = 25°

∵ ∠UOT subtended by arc UT

∴ m of arc UT = m∠UOT

∴ m of arc RUT = 25°

The measure of arc UTS is the sum of the measures of arcs UT and TS

∴ m arc UTS = 25° + 155° = 180°

D.

The measure of arc UTR is the sum of the measures of arcs UT, TS and SR

∴ m arc UTR = 25° + 155° + 25 = 205°

2)

1]

∵ The sum of the measures of the minor and major arcs is 360°

∵ m of minor arc AC = 105°

- Subtract 105 from 360° to find the measure of the major arc CA

∴ m of major arc CA = 360° - 105°

∴ m of major arc CA = 255°

2]

∵ m of major arc AB = 270°

- Subtract 270° from 360° to find the measure of the minor arc AB

∴ m of minor arc AB = 360° - 270°

∴ m of minor arc AB = 90°

8 0

3 years ago