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nalin [4]
3 years ago
13

Need help on this!! Helppp

Mathematics
1 answer:
Tom [10]3 years ago
3 0
ANSWER:
Y=-x-1

EXPLANATION:
Use the formula y=mx+c
m= gradient, c= y intercept
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Solve for X. round to the nearest tenth. 2 5 x 3.5
notka56 [123]
I would say 2.....sorry if I am wrong
6 0
3 years ago
A bag contains white marbles and red marbles, 20 in total. The number of white marbles is 5 more than 2 times the number of red
Nitella [24]

Answer:

15

Step-by-step explanation:

let r represent red marbles then white = 2r + 5 and total is 20, thus

r + 2r + 5 = 20 ( subtract 5 from both sides )

3r = 15 ( divide both sides by 3 )

r = 5 ← number of red marbles

Thus number of white = 20 - 5 = 15

7 0
3 years ago
Find the value of 7v-6 given that -8v-9=7 Simplify your answer as much as possible 7v-6=
evablogger [386]

Answer:

-20

Step-by-step explanation:

-8v-9=7

Add 9 to each side

-8v-9+9=7+9

-8v = 16

Divide by -8

-8v /-8 = 16/-8

v = -2

Now find

7v -6

7(-2) -6

-14 -6

-20

4 0
3 years ago
Read 2 more answers
What is 1/3 of 3/4?
ad-work [718]
I really don't understand what your saying but.....
1/3 = 0.3333333...... and 3/4 = 0.75 = 75%
Hope this helps:)
6 0
3 years ago
Suppose a football is kicked with an initial velocity of 82 ft/sec., at an angle of
satela [25.4K]

Answer:

The position P is:

P = 87\^x + 75\^y ft     <u><em> Remember that the position is a vector. Observe the attached image</em></u>

Step-by-step explanation:

The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity s_0 is:

y(t) = y_0 + s_0t -16t ^ 2

Where y_0 is the initial height = 0 for this case

We know that the initial velocity is:

82 ft/sec at an angle of 58 ° with respect to the ground.

So:

s_0 = 82sin(58\°) ft/sec

s_0 = 69.54 ft/sec

Thus

y(t) = 69.54t -16t ^ 2

The height after 2 sec is:

y(2) = 69.54 (2) -16 (2) ^ 2

y(2) = 75\ ft

Then the equation that describes the horizontal position of the ball is

X(t) = X_0 + s_0t

Where

X_ 0 = 0 for this case

s_0 = 82cos(58\°) ft / sec

s_0 = 43.45 ft/sec

So

X(t) = 43.45t

After 2 seconds the horizontal distance reached by the ball is:

X (2) = 43.45(2)\\\\X (2) = 87\ ft

Finally the vector position P is:

P = 87\^x + 75\^y ft

6 0
3 years ago
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