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irga5000 [103]
3 years ago
8

PLEASE HELP 7TH GRADE MATH

Mathematics
1 answer:
eimsori [14]3 years ago
5 0
Oof... you will need 46,656 to get all 6 prizes .... Throw a die.
Each number on the die depicts one of the 6 prizes.
The number of times you throw describes the number of boxes.
You might be interested in
An arithmetic sequence is shown below. You are not given many terms of this sequence, but you do have enough to fill in the miss
kicyunya [14]

Answer:

B.35

Step-by-step explanation:

The sequence is

14, ,56,....

14 , x , 56

Think of it as 14 + d = x

x+ d = 56

d is the common difference

We now have 2 equations and 2 unknowns

Substitute the first equation in for x   into the second equation

x+d =56

(14+d) +d = 56

Combine like terms

14 + 2d = 56

Subtract 14 from each side

14-14 + 2d = 56-14

2d = 42

Divide by 2

2d/2 =42/2

d = 21

The common difference is 21

Now we can find x

14 + d = x

14+ 21 = x

35 =x

The unknown term is 35

5 0
3 years ago
Find the circumference of a circle whose area is /. A. B. C. D.
notsponge [240]
I just took the test and the correct answer that i got was B
8 0
3 years ago
Read 2 more answers
At the neighborhood grocery, 5 pounds of salmon cost $49. How much would it cost
cluponka [151]

Answer:

$46.06

Step-by-step explanation:

Divide $49 by 5

9.8

So it costs $9.80 for 1 pound of salmon

Multiply $9.80 by 4.7

$46.06

Hope this helped :)

7 0
2 years ago
A positive <br> B negative <br> C none<br> D multiple
egoroff_w [7]
The answer is positive because its is going in the positive column
8 0
2 years ago
Read 2 more answers
In a group of 31 pupils, 4 play the flute only. 14 play the piano only. 7 play neither instrument. A student is selected at rand
solmaris [256]

Answer:

probability the student plays both instruments is [  \frac{6}{31}  ]

<h2>                         <u>Explanation</u>:</h2>

students who play both instruments = total students - flute players - piano players - students who play neither instruments

students who play both instruments

→ 31 - 4 - 14 - 7

→ 6 students play both instruments.

probability:

<h2>→  \boxed{\frac{students- who -play- both- instruments}{total -students} }</h2><h2>→                     \boxed{\frac{6}{31} }</h2>
7 0
2 years ago
Read 2 more answers
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