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3 years ago

Find the cosine of <G

Mathematics

1 answer:

Zinaida [17]3 years ago

3 0

Answer:

cos G = 3/5

Step-by-step explanation:

cos = adjacent sides/ hypotenuse

cos G = FG/ GE

cos G = 3/5

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Natasha packs a single layer of a prism with 5 cubes. Each cube measures 1 centimeter long on each edge. If 5 layers completely

Nastasia [14]

Answer:25

Step-by-step explanation

5 x 5 = 25. Got this problem correct on Imagine Math.

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3 years ago

I have no clue what it is

Orlov [11]

13.95+2.25+2.25+2.25+2.75+2.75+2.75= 28.95

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3 years ago

BEEN STUCK FOR A WHILE PLEASE HELP!! Find the perimeter and area for the triangle. Be sure to write the formula, and use correct

Lady bird [3.3K]

Answer:

Area = 77ft²

Perimeter = 44 9/20 feets

Step-by-step explanation:

Area of a triangle = 1/2 * base * height

Base = 19 1/4 feets = 77/4 feets

Height = 8 feets

Area = 1/2 * 77/4 * 8

Area = (77 * 8) / 8

Area = 77 feet²

Perimeter of a triangle :

Sum of the sides

Perimeter = a + b + c

Perimeter = 19 1/4 + 10 + 15 1/5

Perimeter = 44 + (1/4 + 1/5)

Perimeter = 44 9/20

4 0

3 years ago

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Nady [450]

Answer:

6 i think

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Given that sectheta = -37/12 what is the value of cottheta for pi/2 < theta< pi?

lys-0071 [83]

Answer:

$cotg(\theta) = -\frac{12}{35}$

Step-by-step explanation:

The cotangent of theta is:

$cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}$

For pi/2 < theta< pi

This means that the angle is in the second quadrant. In the second quadrant, the cosine is negative and the sine is positive. This means that the cotangent will be negative.

Secant:

$sec(\theta) = \frac{1}{\cos{\theta}}$

In this question

$sec(\theta) = -\frac{37}{12}$

$-\frac{37}{12} = \frac{1}{\cos{\theta}}$

Using cross multiplication

$-37\cos{\theta} = 12$

$37\cos{\theta} = -12$

$\cos{\theta} = -\frac{12}{37}$

Now we apply the following trigonometric identity:

$\sin{\theta}^{2} + \cos{\theta}^{2} = 1$

$\sin{\theta}^{2} + (-\frac{12}{37})^{2} = 1$

$\sin{\theta}^{2} = 1 - (-\frac{12}{37})^{2}$

$\sin{\theta}^{2} = 1 - \frac{144}{1369}$

$\sin{\theta}^{2} = \frac{1369 - 144}{1369}$

$\sin{\theta} = \pm \sqrt{\frac{1225}{1369}}$

Since the angle is in the second quadrant, the sine is positive.

$\sin{\theta} = \frac{35}{37}$

Finally, the cotangent:

$cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}$

$cotg(\theta) = \frac{-\frac{12}{37}}{\frac{35}{37}}$

$cotg(\theta) = -\frac{12}{35}$

4 0

4 years ago

Read 2 more answers

Find the cosine of <G​

Find the cosine of <G