i know this is a lot but can someone pls help me with these 3 questions. i would very much appreciate it. c:

Solve for x<br> 1 7 1<br> 2<br> х<br> Your answer

ki77a [65]

Answer:

x = 4

Step-by-step explanation:

3x -5 = -2 + 9

-2 + 9 = 7 so now its 3x - 5 = 7

add 5 to the -5 so it cancels itself out. then add the 5 to 7 so it become 12. the you have 3x = 12

divide 12 ÷ 3 = 4

x = 4

8 0

3 years ago

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Company has 189 employees that share an office that has 32 floors. If they built another building for 50 employees, how high sho

iris [78.8K]

Answer:

8 floors

Step-by-step explanation:

The number of employees is directly proportional to the number of floors that each building has.

The first building has 32 floors and it occupies 189 employees. Therefore:

189 α 32

=> 189 = k * 32 = 32k

where k = constant of proportionality

=> k = 189/32

The new building has 50 employees, therefore:

50 = kN

where N = number of floors

=> 50 = 189/32 * N

N = (50 * 32) / 189 ≅ 8 floors

The new building should have 8 floors

5 0

3 years ago

Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm

GuDViN [60]

Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

$P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}$

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones).

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

$P(x \ \textless \ 3) = P(x = 0) + P(x = 1) + P(x = 2)
\\ \indent = \frac{12!}{0!(12-0)!}(0.54)^0 (1-0.54)^{12-0} + \frac{12!}{1!(12-1)!}(0.54)^1 (1-0.54)^{12-1} + \\ \indent \frac{12!}{2!(12-2)!}(0.54)^2 (1-0.54)^{12-2}
\\
\\ \indent = \frac{12!}{(1)(12!)}(0.46)^{12} + \frac{12(11!)}{(1)(11!)}(0.54)(0.46)^{11}+ \frac{12(11)(10!)}{(2)(10!)}(0.54)^2(0.46)^{10}
\\
\\ \indent = (1)(0.46)^{12} + (12)(0.54)(0.46)^{11}+ (66)(0.54)^2(0.46)^{10}
\\ \indent \boxed{P(x \ \textless \ 3) \approx 0.00951836732 }
$

Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or 0.951%.

5 0

3 years ago

Is this true or no plz help

il63 [147K]

Im pretty sure its No.

7 0

3 years ago

you order 4 fish sandwiches and a hamburger. the cost of the hamburger is $2. 50. your total bill before tax is $14.30. write an

Sav [38]

2.95 is the cost of each fish sandwich because 14.30 minus 2.50 is 11.80 and 11.80 divided by 4 is 2.95.

8 0

3 years ago

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