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iragen [17]
3 years ago
5

During a sale , a shop allows 20%

Mathematics
2 answers:
Dafna1 [17]3 years ago
6 0

Answer:

$24

Step-by-step explanation:

original price of a dress = $30

discount = 20%

discount amount = discount% of original price

=20/100 * 30

=30/5

=$6

price that consumer will pay after discount = $30 - $6

=$24

Sindrei [870]3 years ago
3 0

Step-by-step explanation:

6$

MARK ME BRAINLIEST THANKS MY ANSWER PLEASE

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PLEASE HELP ME! Find the cube roots of 125(cos 288° + i sin 288°).
shutvik [7]
◆ COMPLEX NUMBERS ◆

125 ( cos 288 + i sin 288 )  can be written as -

125.e^i( 288) 
125.e^i( 288 +360 ) 
125.e^i( 288+ 720)

[ As , multiples of 360 can be added to an angle without changing any trigonometric functions or sign ]

To find the cube root , take the cube root of above 3 expressions ,

We get -
5 e^( i 96 ) 
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5 e^( i 336 )

Now using Euler's formula , We rewrite above as -

5 ( cos 96 + i sin 96 ) 
5(c os 216 + i sin 216 ) 
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3 years ago
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kifflom [539]

Answer:

The answers to the questions about problem 2 are:

  1. The fraction of the length after Priya stops two times is 3/4.
  2. The fraction of the length after Priya stops four times is 15/16.
  3. Priya will never reach the end of the hallway.

Step-by-step explanation:

The explanation about each answer is below:

1. In the first stop, Priya has walked half of the total length, and there would still be half the hallway, however, when she stops the second time, she has walked the half of the half, I mean:

\frac{1}{2}/2=\frac{1}{4}

If you add the two values you obtain the total distance traveled by Priya:

\frac{1}{2}+\frac{1}{4}= \frac{3}{4}

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\frac{1}{4}/2=\frac{1}{8}

And in the fourth stop she will travel half of the remaining, I mean:

\frac{1}{8}/2=\frac{1}{16}

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3. How we know, the numbers are infinite, in the same forms the distances, by this reason, how the problem says that Priya walks just half of the distance, she will never reach the end because despite she has very near of the end, she will continue walking just half and ever smaller distances.

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Vitek1552 [10]

Answer:

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