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tino4ka555 [31]
3 years ago
7

I know that the base is 2.5 but know what is the height

Mathematics
1 answer:
Mamont248 [21]3 years ago
3 0
We need a picture yo
You might be interested in
Can you help me please ​
MAXImum [283]

there you go hope it helps :)

5 0
2 years ago
Plzzz help me with this I’ll give brainliest
scoray [572]

Answer18:

The quadrilateral ABCD is not a parallelogram

Answer19:

The quadrilateral ABCD is a parallelogram

Step-by-step explanation:

For question 18:

Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)

The slope of a line is given m=\frac{Y2-Y1}{X2-X1}

Now,

The slope of a line AB:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{6-(-1)}{(-4)-(-4)}

m=\frac{7}{0}

The slope is 90 degree

The slope of a line BC:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{6-6}{(-4)-(-1)}

m=\frac{0}{(-3)}

The slope is zero degree

The slope of a line CD:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{(-4)-6}{2-2}

m=\frac{-10}{0}

The slope is 90 degree

The slope of a line DA:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{(-1)-(-4)}{(-4)-(2)}

m=\frac{3}{-6}

m=\frac{-1}{2}

The slope of the only line AB and CD are the same.

Thus, The quadrilateral ABCD is not a parallelogram

For question 19:

Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)

The slope of a line is given m=\frac{Y2-Y1}{X2-X1}

Now,

The slope of a line AB:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{2-3}{3-(-2)}

m=\frac{-1}{5}

The slope of a line BC:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{(-1)-2}{2-3}

m=\frac{-3}{-1}

m=3

The slope of a line CD:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{0-(-1)}{(-3)-2}

m=\frac{-1}{5}

The slope of a line DA:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{3-0}{(-2)-(-3)}

m=3

The slope of the line AB and CD are the same

The slope of the line BC and DA are the same

Thus, The quadrilateral ABCD is a parallelogram

3 0
3 years ago
If the circumference of the circle is 37.68 units, what is the area? (Use 3.14 for pi .)
solniwko [45]

Answer: 113.04

Step-by-step explanation: The equation for the area of a circle is pi r squared so you have to find the radius first. To find the radius, find the diameter first. A way to do this which was easiest for me was dividing 37.68 by pi (3.14), which is 12. Divide the diameter by 2 to find the radius, 6.

Now use the equation from the beginning, pi r squared. So plug in pi as 3.14, then the radius as 6. It is important to always square the radius first, which would be 36. Now multiply 36 by 3.14, and there should be your answer.

7 0
3 years ago
The graph of a line has a slope of -3 and passes through the point (-6,-4).
prohojiy [21]

Answer:

(A) y+4=-3(x+6)

Step-by-step explanation:

The point-slope form of the equation of a line whose slope is m and passes through the point (x_1, y_1) is: y-y_1=m(x-x_1)

Given the point: (x_1, y_1)=(-6,-4)

Slope, m=-3

x_1=-6\\y_1=-4

Substituting these values into:  y-y_1=m(x-x_1), we obtain the point slope form of the equation:

y-(-4)=-3(x-(-6))\\\\y+4=-3(x+6)

The correct option is A.

6 0
3 years ago
What is the interest rate?<br><br>A) 1<br><br>B) 2<br><br>C) 4<br><br>D) 300​
liubo4ka [24]

Answer:

I need more information to calculate it for you

5 0
3 years ago
Read 2 more answers
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