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tino4ka555 [31]
3 years ago
7

I know that the base is 2.5 but know what is the height

Mathematics
1 answer:
Mamont248 [21]3 years ago
3 0
We need a picture yo
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Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
2 years ago
Solve equation please!! :) 10 points
dimulka [17.4K]
3(x-3)-15 = 0
3(x-3) = 15
3x-9 = 15
3x = 24
x = 8
3 0
2 years ago
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30 + 8 = 38 desks

38 x 4 = 152 legs

If you did not add those eight desks then you will have 120 legs.

So, the amount of legs will go up by 32 if you add 8 more desks.

7 0
3 years ago
Mr. Ray is trying to determine the median value of the class averages for his math classes. First, he must list the class averag
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a is the answer

all you need to do is place the numbers from the lowest amount to the highest amount :)



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3 years ago
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100 POINTS!! Which of these is equivalent to the following expression? 2m + 8w + 10m - 3w
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Answer:

thou answer is option C

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