there you go hope it helps :)
Answer18:
The quadrilateral ABCD is not a parallelogram
Answer19:
The quadrilateral ABCD is a parallelogram
Step-by-step explanation:
For question 18:
Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)
The slope of a line is given m=
Now,
The slope of a line AB:
m=
m=
m=
The slope is 90 degree
The slope of a line BC:
m=
m=
m=
The slope is zero degree
The slope of a line CD:
m=
m=
m=
The slope is 90 degree
The slope of a line DA:
m=
m=
m=
m=
The slope of the only line AB and CD are the same.
Thus, The quadrilateral ABCD is not a parallelogram
For question 19:
Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)
The slope of a line is given m=
Now,
The slope of a line AB:
m=
m=
m=
The slope of a line BC:
m=
m=
m=
m=3
The slope of a line CD:
m=
m=
m=
The slope of a line DA:
m=
m=
m=3
The slope of the line AB and CD are the same
The slope of the line BC and DA are the same
Thus, The quadrilateral ABCD is a parallelogram
Answer: 113.04
Step-by-step explanation: The equation for the area of a circle is pi r squared so you have to find the radius first. To find the radius, find the diameter first. A way to do this which was easiest for me was dividing 37.68 by pi (3.14), which is 12. Divide the diameter by 2 to find the radius, 6.
Now use the equation from the beginning, pi r squared. So plug in pi as 3.14, then the radius as 6. It is important to always square the radius first, which would be 36. Now multiply 36 by 3.14, and there should be your answer.
Answer:
(A) y+4=-3(x+6)
Step-by-step explanation:
The point-slope form of the equation of a line whose slope is m and passes through the point
is: 
Given the point: 
Slope, m=-3

Substituting these values into:
, we obtain the point slope form of the equation:

The correct option is A.
Answer:
I need more information to calculate it for you