Answer:
Explanation:
The forces acting on the crates when the train starts stopping are their weights, the normal force from the train, the static frictional force and the fictional force that is produced by the deceleration of the train. As the gravitational force, this fictional force is equal to the mass of the crates multiplied by the magnitude of the acceleration of the train. So, the equations of motion of the crates will be:
Since the static frictional force is , we get:
So we have a limit to the acceleration of the train. Now, we have to know the distance traveled by the train when it is stopping. Then, we use the kinematic formula:
Now we solve for the acceleration to combine this equation to the inequality we got before:
And solve for x:
Since we are looking for the minimum value for x, we consider the case in which that inequality becomes an equation:
Before we finish, we have to convert the unities of the initial velocity to meters per second:
Finally, we plug in the known values to get :
It means that the train can be stopped at a minimum distance of 36.2m at constant acceleration without causing the crates slide over the floor.
The equation for Kc:
Kc = [C]² / [A] [B]
Let the equilibrium concentration of C be x
Then,
the equilibrium concentration of A = 1-x
the equilibrium concentration of B = 1-x
The equation becomes:
4 = x² / (1 - x)²
3x² - 8x + 4 = 0
x = 2, x = 2/3
The first answer is not possible so x = 2/3
[A] = 1 - 2/3 = 1/3
[B] = 1 - 2/3 = 1/3
Answer:
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Explanation:
Divide both sides by 1.5 to get..
1.33sin(25°)/1.5 = sin(θ)
Hence, by setting both sides by the inverse of sine...
arcsin(sin(θ)) = arcsin(1.33sin(25°)/1.5)
θ ≈ 22.01°
I hope this helps!
To solve this problem it is necessary to apply the concepts related to the energy released through the mass defect.
Mass defect can be understood as the difference between the mass of an isotope and its mass number, representing binding energy.
According to the information given we have that the reaction presented is as follows:
The values of the atomic masses would then be:
Th = 232.037146 u
Ra = 228.028731 u
He = 4.0026
The mass difference of the reaction would then be represented as
From the international measurement system we know that 1 atomic mass unit is equivalent to 931.5 MeV,
Therefore the energy is 5.414MeV