3 years ago

What is acceleration?

Physics

2 answers:

RSB [31]3 years ago

8 0

Answer:

Acceleration is the rate of change of velocity.

Kisachek [45]3 years ago

7 0

Acceleration is the force of something moving, or acceleration can be how fast an object is going!

You might be interested in

Protons Neutrons Electrons Location Charge Size

igor_vitrenko [27]

Protons are positive, and neutrons are negative, electrons are neutral. I’m not sure about the rest but I hope that helps for now

6 0

2 years ago

Please need help on this

neonofarm [45]

Answer:

Explanation:

Geothermal energy is heat driven within the sub-surface of the earth. Water and/or steam carry the geothermal energy to the earth surface.

6 0

3 years ago

The unit of energy is a derived unit why

olga2289 [7]

Answer:

The unit of energy is joule which depends upon the fundamental unit kg, m and sec. So, the unit of energy is a derived unit.

Explanation:

7 0

3 years ago

Read 2 more answers

A proton is propelled at 4×106 m/s perpendicular to a uniform magnetic field. 1) If it experiences a magnetic force of 4.8×10−13

tia_tia [17]

Answer:

B = 0.75 T

Explanation:

As we know that the force on a moving charge in magnetic field is given by the formula

$F = qvB$

here we have

$B = \frac{F}{qv}$

here we know that

$F = 4.8 \times 10^{-13} N$

$q = 1.6 \times 10^{-19} C$

$v = 4 \times 10^6 m/s$

now from above equation we have

$B = \frac{4.8 \times 10^{-13}}{(1.6 \times 10^{-19})(4 \times 10^6)}$

$B = 0.75 T$

8 0

3 years ago

An object propelled upwards with an acceleration of 2.0 m / s ^ 2 is launched from rest. After 6 seconds the fuel runs out. Dete

dezoksy [38]

Answer:43.34 m

Explanation:

Given

acceleration(a) $=2 m/s^2$

Initial Velocity(u)=0 m/s

After 6 s fuel runs out

Velocity after 6 s

v=u+at

$v=0+2\times 6=12 m/s$

After this object will start moving under gravity

height reached in first 6 s

$s=ut+\frac{at^2}{2}$

$s=0+\frac{2\times 6^2}{2}$

s=36 m

After fuel run out distance traveled in upward direction is

$v^2-u^2=2as_0$

here v=0

u=12 m/s

$a=9.8 m/s^2$

$0-12^2=2(-9.8)(s)$

$s_0=\frac{144}{2\times 9.8}=7.34 m$

$s+s_0=36+7.34=43.34 m$

7 0

3 years ago

What is acceleration?​

What is acceleration?