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Kruka [31]
3 years ago
11

What is the answer to this​

Mathematics
1 answer:
AfilCa [17]3 years ago
8 0

Answer:

B.

Step-by-step explanation:

This answer makes the most sense to me. It is the closest to the areas of the sapes I found.

Hope it's correct!

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Aboslute value|10 blocks| + |3 blocks| + |-8 blocks| + |2 blocks| + |-7 blocks| + |4 blocks| + |-4 blocks| = ?
Elza [17]
Absolute or modulus always gives a positive number.
For example, when I take absolute value of 4, I get
|4| = 4 and when I take absolute value of -4, I get |-4| = -(-4) = 4.

Therefore, no matter what the sign of quantity is, absolute or modulus will always make it positive. 
Therefore,
<span>|10 blocks| + |3 blocks| + |-8 blocks| + |2 blocks| + |-7 blocks| + |4 blocks| + |-4 blocks| = 10 + 3 -(-8) + 2 -(-7) + 4 -(-4) = 10+3+8+2+7+4+4 = 38</span>
5 0
3 years ago
Y'all ineed jesus:
oksano4ka [1.4K]
The correct answer is:  [A]:
______________________________________________________
    "<span>Jane, because there will be variability in the responses collected."
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7 0
3 years ago
Read 2 more answers
PLEASE ANSWER ASAP!! Will give brainliest!!
OLga [1]

Answer:

B.(2,1)

Step-by-step explanation:

The line segment AB will translate onto segment AB' by the translation,

(x+2, y+1)

You add 2 to the x value and 1 to the y value of segment AB.

3 0
3 years ago
A highly selective boarding school will only admit students who place at least 2.5 standard deviations above the mean on a stand
tresset_1 [31]

Answer:

260 is the minimum score.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 200

Standard Deviation, σ = 24

We are given that the distribution of test score is a bell shaped distribution that is a normal distribution.

Least marks required for admission in boarding school is 2.5 standard deviations above the mean.

Thus, we can calculate the minimum score as:

=\mu + 2.5(\sigma)\\=200 + 2.5(24)\\=260

Thus, 260 is the minimum score that an applicant must make on the test to be​ accepted.

4 0
3 years ago
Find X such that f(x)=0 for f(x)= -2x^2-x
Leokris [45]

Answer:

x=\{-\frac{1}{2} ,\:0\}

Step-by-step explanation:

f(x) =-2x^2 -x\\plug \: f(x) =0\\0= -2x^2 -x\\2x^2 + x = 0\\x(2x+1) = 0\\\therefore x =0 \: or \: 2x+1 = 0\\\therefore x =0 \: or \: 2x = -1\\\\\therefore x =0 \: or \: x = -\frac{1}{2} \\\\x=\{-\frac{1}{2} ,\:0\}

6 0
3 years ago
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