Question

Find X such that f(x)=0 for f(x)= -2x^2-x

Answer 1

Answer:

$x=\{-\frac{1}{2} ,\:0\}$

Step-by-step explanation:

$f(x) =-2x^2 -x\\plug \: f(x) =0\\0= -2x^2 -x\\2x^2 + x = 0\\x(2x+1) = 0\\\therefore x =0 \: or \: 2x+1 = 0\\\therefore x =0 \: or \: 2x = -1\\\\\therefore x =0 \: or \: x = -\frac{1}{2} \\\\x=\{-\frac{1}{2} ,\:0\}$