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patriot [66]
2 years ago
8

Determine the axis of symmetry of the Quadratic equation.

Mathematics
2 answers:
Marat540 [252]2 years ago
7 0
B/X=2
OWA OWA 20 minimum word
aniked [119]2 years ago
5 0

Answer:

option B : X=2

Step-by-step explanation:

Because the line U touches on X:2

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A television network is about to telecast a new television show. Before a show is launched, the network airs a pilot episode and
Basile [38]

Answer:

(E) 0.83

Step-by-step explanation:

We will solve it using conditional probability.

Let A be the event that a TV show is successful.

P(A) = 0.5

A' be event that the show is unsuccessful

P(A') =0.5

Let B be the event that the response was favorable

P(B) = 0.6

Let B' be the event that the response was unfavorable/

P(B') = 0.4

P(A∩B) = 0.5 and P(A∩B') = 0.3

We need to find new show will be successful if it receives a favorable response.

P(A/B) = \frac{P(A∩B)}{P(B)}

           = 0.5/0.6

           = 0.833

7 0
3 years ago
Read 2 more answers
What is 5m2- 15m- 200
vitfil [10]

Answer:

5(m + 5) (m - 8)

Step-by-step explanation:

5m2- 15m- 200

Start by pulling 5 out.

5(m^2 - 3m - 40)

We consider all factors of 40  

1    40

2   20

4    10

5     8

Based on the middle term we know that 5   and 8 are our best option.

5(m     5) (m     8)

We know the signs have to be one + and one -  because a - * - = + and + * + = +

Since 5 - 8 would give us -3 we know that our answer is

5(m + 5) (m - 8)

3 0
3 years ago
It has been said that newspapers are disappearing, replaced by various electronic media. In 2004, newspaper circulation (the num
shutvik [7]

Answer:

A. y=-1.2x+59

B. 42.2 million

Step-by-step explanation:

Part A:

Given:

Newspapers circulated in year 2004, y_{1}=59\textrm{ million}

Newspapers circulated in year 2014, y_{2}=47\textrm{ million}

Let the time x start at the year 2004. So, x_{1}=0

For the year 2014, x_{2}=2014-2004=10

Therefore, linear relationship between newspapers circulated and time passed since 2004 is given as:

y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}(x-x_{1})\\y-59=\frac{47-59}{10-0}(x-0)\\y-59=-\frac{12}{10}x\\y=-1.2x+59

Therefore, the equation describing the relationship is: y=-1.2x+59

Part B:

For the year 2018, x=2018-2004=14

Plug in 14 for x in the above equation and solve for y. This gives,

y=-1.2(14)+59\\y=-16.8+59\\y=42.2

Therefore, in the year 2018, the newspaper circulation will be 42.2 million.

8 0
3 years ago
3m-2n+4p=15<br> m-n+p=3<br> m+4n-5p=0
Viefleur [7K]
What you need help in
6 0
3 years ago
Which expression is equivalent to the expression below?
Annette [7]

Answer: B and D

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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