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Arada [10]
3 years ago
6

If $5,000 is invested at 6% interest, how much money must be invested at 8% interest so that the total interest from the two inv

estments is $660 after one year?
Mathematics
1 answer:
disa [49]3 years ago
7 0

Answer:

$4500

Step-by-step explanation:

Simple Interest formula = Principal × Rate × Time

Let the amount of the money invested at 8% Interest = x

Hence:

$5000 × 6% × 1 + x × 8% × 1 = $660

$300 + 0.08x = $660

0.08x = $660 - $300

0.08x = $360

x = $360/0.08

x = $4500

Therefore , the amount that must be invested at 8% interest is $4500

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3 years ago
Civil an airport, a factory, and a shopping center are at the vertices of a right triangle formed by three highways. the airport
vekshin1

Answer:

<em>The shortest possible length for the service road is 2.88 miles.</em>

Step-by-step explanation:

According to the below diagram, A, B and C are the positions of airport, shopping center and factory respectively.

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tan(\angle ACB)=\frac{AB}{BC} \\ \\ tan(\angle ACB)= \frac{3.6}{4.8}=0.75\\ \\ \angle ACB= tan^-^1(0.75)=36.8698.... degree

The shortest possible length for the service road from the shopping center to the highway that connects the airport and factory is BD.

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Now in right triangle BCD

Sin(\angle ACB)=\frac{BD}{BC}\\ \\ Sin(36.8698...)=\frac{BD}{4.8}\\ \\ BD=4.8*Sin(36.8698...)=2.88

So, the shortest possible length for the service road is 2.88 miles.

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4 years ago
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4 years ago
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