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A = L^2
A = L^2 = 2^2 + 4^2 (Pythagorean’s theorem)
A = L^2 = 20
Therefore the area of the square is 20 units square.
Answer:
x ∈ (-∞, -1) ∪ (1, ∞)
Step-by-step explanation:
To solve this problem we must factor the expression that is shown in the denominator of the inequality.
So, we have:

So the roots are:

Therefore we can write the expression in the following way:

Now the expression is as follows:

Now we use the study of signs to solve this inequality.
We have 3 roots for the polynomials that make up the expression:

We know that the first two are not allowed because they make the denominator zero.
Observe the attached image.
Note that:
when 
when 
and
is always 
Finally after the study of signs we can reach the conclusion that:
x ∈ (-∞, -1) ∪ (1, 2] ∪ [2, ∞)
This is the same as
x ∈ (-∞, -1) ∪ (1, ∞)