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balandron [24]
3 years ago
9

How can the percent yield be used to determine the actual yield of a chemical reaction

Chemistry
1 answer:
Alexeev081 [22]3 years ago
5 0

Answer: Theoretical yield is calculated based on the stoichiometry of the chemical equation. The actual yield is experimentally determined. The percent yield is determined by calculating the ratio of actual yield/theoretical yield.

Explanation:

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As you go down group one of the periodic table, the reactions become and more
Lady bird [3.3K]

Answer:

vigorous

Explanation:

As you go down group one of the periodic table, the reactions become and more vigorous.

3 0
2 years ago
Which is the smallest particle into which a compound can be broken down and still remain the same compound? A. atom B. mixture C
Andre45 [30]
The smallest would be a compound
4 0
3 years ago
What happens in a chemical change that does not occur in a physical change?
Andrej [43]

Answer:

In a chemical reaction, there is a change in the composition of the substances in question; in a physical change there is a difference in the appearance, smell, or simple display of a sample of matter without a change in composition. Although we call them physical "reactions," no reaction is actually occurring.

6 0
3 years ago
26.0 g of a liquid that has a density of 1.44 g/mL needs to be measured out in a graduated cylinder. what volume should be used
Vaselesa [24]
As Density = Mass/Volume
Mass = 26.0g 
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4 0
3 years ago
Read 2 more answers
A solution is made by dissolving 58.125 g of sample of an unknown, nonelectrolyte compound in water. The mass of the solution is
e-lub [12.9K]

Answer:

molecular weight (Mb) = 0.42 g/mol

Explanation:

mass sample (solute) (wb) = 58.125 g

mass sln = 750.0 g = mass solute + mass solvent

∴ solute (b) unknown nonelectrolyte compound

∴ solvent (a): water

⇒ mb = mol solute/Kg solvent (nb/wa)

boiling point:

  • ΔT = K*mb = 100.220°C ≅ 373.22 K

∴ K water = 1.86 K.Kg/mol

⇒ Mb = ? (molecular weight) (wb/nb)

⇒ mb = ΔT / K

⇒ mb = (373.22 K) / (1.86 K.Kg/mol)

⇒ mb = 200.656 mol/Kg

∴ mass solvent = 750.0 g - 58.125 g = 691.875 g = 0.692 Kg

moles solute:

⇒ nb = (200.656 mol/Kg)*(0.692 Kg) = 138.83 mol solute

molecular weight:

⇒ Mb = (58.125 g)/(138.83 mol) = 0.42 g/mol

8 0
3 years ago
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