Answer:
(3)(c) + 43 ≥ 100
Step-by-step explanation:
Given:
Total number of friends = 3 friends
Number of card already have = 43
Total number of card at least want to collect = 100
Find:
Inequality
Computation:
Assume;
Same number of card each friend collect = c
Total number of card at least want to collect ≤ (Total number of friends)(Same number of card each friend collect) + Number of card already have
Total number of card at least want to collect ≤ (3)(c) + 43
100 ≤ (3)(c) + 43
(3)(c) + 43 ≥ 100
Answer:
C 160
Step-by-step explanation:
hop it helped you in any way
Answer:
Step-by-step explanation:
B
2
3
Let the distance of two consecutive stones are x, x+1.
In ΔBCD, we have
tan60
o
=
x
h
⇒x=
3
h
.....(i)
In ΔABC, we have
tan30
o
=
x+1
h
⇒
3
1
=
x+1
h
⇒
3
h
+1=
3
h ......[from equation (i)]
⇒
3
2h
=1
⇒h=
2
3
km
solution
