All categories

3 years ago

How many different ways can you write a fraction that has a numerator of 2 as a sum of fractions? Explain.

Mathematics

1 answer:

zhenek [66]3 years ago

4 0

Answer:

Step-by-step explanation:

1/5 + 1/5 = 2/5

1/7 + 1/7 = 2/7

1/3 + 1/3 = 2/3

There are an infinite number of these fractions. They must be 1 and 1 in the numerator, and the denominator must be relatively prime to 2. The examples I have picked are prime in the denominator, but the rule is not without many exceptions. For example

1/9 + 1/9 = 2/9

I don't think you can pick an even denominator because it will reduce when put with two. Oh wait 2/18 + 2/18 = 4/18 = 2/9 But these could be reduced before adding. Still, it might count. It depends on who is marking the question.

What about an odd and even denominator?

1/9 + 1/18 = 3/18 = 1/6 There must be something that works, but I can't come up with an example.

You might be interested in

Samuel wants to buy cookies for his friend. The diameter of a cookie is 20 inches. What is the cookies area? Round to the neares

olya-2409 [2.1K]

Answer:

314.16

Step-by-step explanation:

Area=πr2

d=2r

Solving for Area

A=1

4πd2=1

4·π·202≈314.15927

7 0

2 years ago

What is the probability that the first marbles you choose is red and the second is blue

ella [17]

Answer:

2/9

Step-by-step explanation:

5 0

1 year ago

S = vt + 16t^2, solve for v.

Phoenix [80]

$S=vt+16t^2\ \ \ \ \ | subtract\ 16t^2\\\\
S-16t^2=vt\ \ \ \ \ | divide\ by\ t\\\\
\frac{S-16t^2}{t}=v\\\\\Solution\ is\ v=\frac{S-16t^2}{t}.$

7 0

3 years ago

Determine whether the integral is convergent or divergent. ∫[infinity] 2 e^−1/x / x^2 dx : O Convergent O divergent If it is con

monitta

Let $f(x)=e^{-1/x}$ . Then $f'(x)=\frac1{x^2}e^{-1/x}>0$ for all $x\ge2$ , so $f$ is strictly increasing. As $x\to\infty$ , $e^{-1/x}\to e^0=1$ , so $f$ is bounded above by 1. This is to say,

$e^{-1/x}$

and the integral of $\frac1{x^2}$ converges over the same domain, so this integral must also converge by comparison.

We have, by setting $y=-\frac1x$ ,

$\displaystyle\int_2^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx=\int_{-1/2}^0e^y\,\mathrm dy=e^0-e^{-1/2}=1-\frac1{\sqrt e}$

8 0

2 years ago

Simplify the expression completely.<br><br> 16x-12x

romanna [79]

These are like terms, meaning that they are completely the same disregarding the coefficient.

To combine like terms, add the coefficients.
16+(-12)=4

Final answer: 4x

6 0

3 years ago