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fenix001 [56]
2 years ago
14

pete took out a 48 month loan for $5,200 to buy a used mortorcycle. if the simple interest rate is 8.5 % how much will he have p

aid in total at the end of the loan?
Mathematics
2 answers:
alexdok [17]2 years ago
6 0

Answer:he would have paid $6,968.00

Step-by-step explanation:

5200x0.085=442. 42/12=4. 4x422=1768

1768+5200=6968

solong [7]2 years ago
3 0

Answer:

23904 (please correct me if i'm wrong, i'm a bit rough on this)

Step-by-step explanation:

5,800 x 0.085 (or 8.5%) = 493

493 x 48 = 23904

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andrea went on a shopping spree and bought 5 pairs of jeans 4 t shirts and 2 pairs of shoes the jeans cost 8 dollars each the t
MatroZZZ [7]

Answer:$76

Step-by-step explanation:

JEANS: (5x8)= 40

SHIRTS:(4x6)= 24

SHOES BUY ONE GET ONE FREE: (12x2 - 12)= 12

40 + 24 + 12 = 76

3 0
3 years ago
A local golf course charges members $35 an hour for the first four hours, $40 an hour for the next fou
Slav-nsk [51]

Answer:

Step-by-step explanation:

35x4 =140

40x4=160    +

----------------

300$ all together

Hope this helps

And don't forget to mark as brainliest

5 0
2 years ago
Solve.
Oduvanchick [21]

Answer:

Step-by-step explanation:

There are several approach to solving a quadratic equation; factorization, completing the square, the use of 'the almighty formula etc. Though i didn't see the steps you followed in solving, but from your answer, it is obvious you made good attempt but something is missing, your answer should be (5+√57)/2 or (5-√57)/2

5 0
3 years ago
Read 2 more answers
Harvey Alson invested $7,500 in a 2-year CD that pays 6% interest compounded quarterly. What is the amount of interest that Harv
irga5000 [103]
A=7,500×(1+0.06÷4)^(4×2)
A=8,448.69

Interest earned=8,448.69−7,500
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5 0
3 years ago
Read 2 more answers
Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
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