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3 years ago

Mr. Fernandez is mixing soil for his garden. He wants the soil to be in the

Mathematics

1 answer:

Alex17521 [72]3 years ago

3 0

Answer:

0.4 to 1

Step-by-step explanation:

2 1/2=2.5

you do 1 divided by 2.5 or 1/2.5 and you get 0.4 then add the unit rate of 1.

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What is each measure of the rhombus?

Elodia [21]

A. 15
b. 26

d. 41
e. 82
f. 98

h. 49

5 0

3 years ago

A map has a scale of 4 inches: 25 miles how far are two cities if they are 120 miles apart

IrinaK [193]

Answer: 19.2 inches

Step-by-step explanation:

Make a proportion:

4/25 = x/120

cross multiply

480 = 25x

Divide both sides by 25

X= 19.2

4 0

3 years ago

What is the slope of the line that passes through the points (7, -4) and (7, 0)? Write your answer in the simplest form.

olga55 [171]

Answer:

The slop is undefined

i.e. $m=\infty$

Step-by-step explanation:

Considering the slope formula

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

As the points are (7, -4) and (7, 0)

Here:

(x₁, y₁) = (7, -4)

(x₂, y₂) = (7, 0)

$\mathrm{When\:}y_1\ne \:y_2\mathrm{\:and\:}\:x_1=x_2\mathrm{\:the\:slope\:is\:}\infty$

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$=\frac{\left(0-\left(-4\right)\right)}{\left(7-7\right)}$

$=\frac{0-\left(-4\right)}{0}$

$=\infty$

Therefore, the slop is undefined i.e. $m=\infty$

5 0

3 years ago

PLS TRY TO ANSWER ASAP.

Harrizon [31]

Answer:

0.075 m/min

Explanation:

You need to use derivatives which is an advanced concept used in calculus.

1. Write the equation for the volume of the cone:

$V=\dfrac{1}{3}\pi r^2h$

2. Find the relation between the radius and the height:

r = diameter/2 = 5m/2 = 2.5m

h = 5.2m

h/r =5.2 / 2.5 = 2.08

3. Filling the tank:

Call y the height of water and x the horizontal distance from the axis of symmetry of the cone to the wall for the surface of water, when the cone is being filled.

The ratio x/y is the same r/h

x/y=r/h

y = x . h / r

The volume of water inside the cone is:

$V=\dfrac{1}{3}\pi x^2y$

$V=\dfrac{1}{3}\pi x^2(2.08)\cdot x\\\\\\V=\dfrac{2.08}{3}\pi x^3$

4. Find the derivative of the volume of water with respect to time:

$\dfrac{dV}{dt}=2.08\pi x^2\dfrac{dx}{dt}$

5. Find x² when the volume of water is 8π m³:

$V=\dfrac{2.08}{3}\pi x^3\\\\\\8\pi=\dfrac{2.08}{3}\pi x^3\\\\\\ 11.53846=x^3\\ \\ \\ x=2.25969\\ \\ \\ x^2=5.1062$ m²

6. Solve for dx/dt:

$1.2m^3/min=2.08\pi(5.1062m^2)\dfrac{dx}{dt}$

$\dfrac{dx}{dt}=0.03596m/min$

7. Find dh/dt:

From y/x = h/r = 2.08:

$y=2.08x\\\\\\\dfrac{dy}{dx}=2.08\dfrac{dx}{dt}\\\\\\\dfrac{dy}{dt}=2.08(0.035964m/min)=0.0748m/min\approx0.075m/min$

That is the rate at which the water level is rising when there is 8π m³ of water.

4 0

3 years ago

Given that p(b|a)=0.75 and p(a)=0.35, what is p(b and a)

Nikitich [7]

Answer:

1.0125

Step-by-step explanation:

Since b/a is 0.75 and a is given as 0.35

Then let's start by solving for b

Ok...how

b/a=0.75

a=0.35

Then make b the subject of formula

b=0.75×a

Then substitute the value of a

b=0.75×0.35

b=0.2625

Let's continue

b and a means b + a

0.75+0.2625

1.0125

Therefore the final answer is 1.0125

6 0

4 years ago