In the first few steps for deriving the quadratic formula left side of the equation due to the distributive property for balancing the equation.
<h3>What is quadratic equation?</h3>
A quadratic equation is the equation in which the highest power of the variable is two.
Here, The first few steps in deriving the quadratic formula are shown in the table.
Use the substitution property of equality to solve it further,
-c=-ax² +bx
Now factor out the term a, to solve further as,
- c = a (x² + b/a x)
for half of the b value and square it to determine the constant of the perfect square trinomial as,
(b/2a)² = b²/4a²
Now the distributive property needs to be applied to determine the value to add to the left side of the equation to balance the sides of the equation.
-c + b²/4a² = a(x² + b/a x + b²/4a² )
Thus, the distributive property needs to be applied to determine the value to add to the left side of the equation to balance the sides of the equation.
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Answer:
If you pick the number 2, you will get (2) - 10 = 8
But the way he said it, it would be: (2) - 2 * 5 = 0
The correct way would be to write the expression: (x - 3) * 5
The answer is 0.5.
X is the input and f(x) is the output. Between -3 and -2 the difference is 0.5. Because it goes from -0.5 to 1
Answer:
Explanation:
<u>1) Calculate the volume of the water in the tank.</u>
- Area of the base of the tank: B = 7 ft × 4 ft = 28 ft²
- Height of the tank: H = 9 in = 9 in × 1 ft / 12 in = 0.75 ft
- Volume of the tank: V = area of the base × height = B × H = 28 ft² × 0.75 ft = 21 ft³.
<u>2) Calculate the weight of 21 ft³ of water.</u>
Since this is not a chemistry question but a math question, I will not use the fomula of density but set a proportion with one unknown:
- 62.4 lb / 1 ft³ = x / 21 ft³
Solve for x:
- x = 21 ft³ × 64 lb / ft³ = 1,310.4 lb.
So, rounding to the next integer, the water in the tank weighs 1,310 pounds, when it is full.
