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lidiya [134]
3 years ago
14

The question is below

Mathematics
1 answer:
Anna35 [415]3 years ago
8 0

Answer:

12) A = 27

13) B =  36

14) C = 25

15) D = 30

Step-by-step explanation:

We need to complete the ratio tables

We are given:

Footballs 15   5   20   C     D

Baseballs A   9    B    45   54

The table shows the ratio of footballs to baseballs.

We are given the ratio \frac{Football}{Baseball}=\frac{5}{9}

All other ratios will also be simplified to get \frac{5}{9}

12) Calculate A

Footballs = 15

Baseballs = A

Common ratio is 5/9, we need to find a number that multiplies by 5 to get 15, same number will be multiplied by denominator to get A.

We know that \frac{5\times3}{9\times3}= \frac{15}{27}

So, A = 27

13) Calculate B

Footballs = 20

Baseballs = B

Common ratio is 5/9, we need to find a number that multiplies by 5 to get 20, same number will be multiplied by denominator to get B.

We know that \frac{5\times4}{9\times4}= \frac{20}{36}

So, B = 36

14) Calculate C

Footballs = C

Baseballs = 45

Common ratio is 5/9, we need to find a number that multiplies by 9 to get 45, same number will be multiplied by numerator to get C.

We know that \frac{5\times5}{9\times5}= \frac{25}{45}

So, C = 25

15) Calculate D

Footballs = D

Baseballs = 54

Common ratio is 5/9, we need to find a number that multiplied by 9 to get 54, same number will be multiplied by numerator to get D.

We know that \frac{5\times6}{9\times6}= \frac{30}{54}

So, D = 30

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shepuryov [24]
Sorry I’m wrong I took geometry like 3 years ago so I might forget some

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8 0
3 years ago
in a square garden plot (with an area of 400 sq ft)deer fencing priced at $1.50 per foot is to be installed around the plot. if
mina [271]

We have a square garden of 400 square foot.

The area of a square is:

A=x^2

where x: side length.

In this case:

\begin{gathered} A=400=x^2 \\ x=\sqrt[]{400}=20\text{ ft} \end{gathered}

The perimeter of the square is the sum of the lengths of the sides of the square. As they are all equal, we can write:

P=4x=4\cdot20=80\text{ ft}

The fencing is priced at $1.50 per foot. If we add the 7% sales tax to this price we get:

C=1.50\cdot(1+0.07)=1.50\cdot1.07=1.605\text{ \$/ft}

The fencing will be installed in all the perimeter (80 ft).

We can calculate the total cost by multiplying the sales price ($1.605 per foot) and the perimeter (80 ft):

F=C\cdot P=1.605\frac{\text{\$}}{\text{ft}}\cdot80\text{ ft}=\$128.40

Answer: the fencing will cost a total of $128.40

8 0
1 year ago
Lara randomly surveyed 15 students
Rina8888 [55]

Answer:

hii

Step-by-step explanation:

yes it represents school population

Hope this helps you

Thank you

Gudni8

6 0
3 years ago
Becky bought a bag of mixed chocolates that have either a toffee or nut center. Her and four friends pulled out the first eleven
denpristay [2]

Answer

Part A

Probability that the next chocolate will have a toffee center = (8/11)

Part B

Expected number of chocolates with nut centers = 18 nut centers

Part C

Probability of the picking three consecutive chocolates with nut centers

= (27/1331)

= 0.0203

Explanation

The first 11 chocolates had 8 toffee and 3 nut centers.

The result from these first 11 picks will be used to calculate the rest of the probability or make predictions.

So, for the first part of the question.

Probability that the next chocolate will have a toffee center

= (8/11)

Part B

If there are 66 chocolates left in the bag, how many do you expect to have a nut center?

Probability of picking a chocolate with nut center = p = (3/11)

Number of chocolates in total = n = 66

Expected number of chocolates with nut centers

= np

= (66) (3/11)

= 18 nut centers

Part C

What is the probability that the next 3 pulled do have a nut in the center?​

Probability of picking a chocolate with nut center = (3/11)

Probability of the picking three consecutive chocolates with nut centers

= (3/11) × (3/11) × (3/11)

= (27/1331)

= 0.0203

Hope this Helps!!!

3 0
1 year ago
Your parents heard about the success of your business and they want to give you an additional $300 to put toward your business.
Harrizon [31]

We want to write an inequality that reflects that you can spend between $150 and $450.

We will find the inequality:

450 ≥ 11*t + 18 ≥ 150

And solving this we have:

39.3  ≥ t  ≥ 12

Now let's see how to solve this problem.

So, we start with the inequality:

150 ≥ 11*t + 18.

I assume that:

11*t + 18

Is the amount you will spend, and 150 is the initial maximum amount that you can spend.

Now your parents give you $300, so the maximum goes from $150 to $450, and we also have a minimum of $150 (because the problem says it).

Then we write the inequality as:

450 ≥ 11*t + 18 ≥ 150

We can solve this for t:

450 - 18 ≥ 11*t  ≥ 150  - 18

432  ≥ 11*t  ≥  132

432/11  ≥ t  ≥ 132/11

39.3  ≥ t  ≥ 12

If you want to learn more, you can read:

brainly.com/question/20382422

7 0
2 years ago
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