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lidiya [134]
3 years ago
14

The question is below

Mathematics
1 answer:
Anna35 [415]3 years ago
8 0

Answer:

12) A = 27

13) B =  36

14) C = 25

15) D = 30

Step-by-step explanation:

We need to complete the ratio tables

We are given:

Footballs 15   5   20   C     D

Baseballs A   9    B    45   54

The table shows the ratio of footballs to baseballs.

We are given the ratio \frac{Football}{Baseball}=\frac{5}{9}

All other ratios will also be simplified to get \frac{5}{9}

12) Calculate A

Footballs = 15

Baseballs = A

Common ratio is 5/9, we need to find a number that multiplies by 5 to get 15, same number will be multiplied by denominator to get A.

We know that \frac{5\times3}{9\times3}= \frac{15}{27}

So, A = 27

13) Calculate B

Footballs = 20

Baseballs = B

Common ratio is 5/9, we need to find a number that multiplies by 5 to get 20, same number will be multiplied by denominator to get B.

We know that \frac{5\times4}{9\times4}= \frac{20}{36}

So, B = 36

14) Calculate C

Footballs = C

Baseballs = 45

Common ratio is 5/9, we need to find a number that multiplies by 9 to get 45, same number will be multiplied by numerator to get C.

We know that \frac{5\times5}{9\times5}= \frac{25}{45}

So, C = 25

15) Calculate D

Footballs = D

Baseballs = 54

Common ratio is 5/9, we need to find a number that multiplied by 9 to get 54, same number will be multiplied by numerator to get D.

We know that \frac{5\times6}{9\times6}= \frac{30}{54}

So, D = 30

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Dominik [7]

Answer:

Step-by-step explanation:

surface area of one  can 2πrh+2πr²

=2πr(h+r)

≈2×3.14×3/2(4.25+1.5)

≈9.42(5.75)

≈54.165 in²

number of cans=1000/54.165

=18 cans

material used=18×54.165≈975 in²

material left=1000-975=25 in²

3 0
2 years ago
A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled
klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5

The standard deviation of the sample is calculated as:

s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8

Then, we can calculate the standard error of the mean as:

\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5

6 0
3 years ago
640 rounded to the nearest tens
Reptile [31]

It is rounded to the nearest tens. You can only round when you have 1,9. Hope I helped

6 0
3 years ago
Read 2 more answers
I NEED HELP ASAP BEFORE IT TIMES OUT!
padilas [110]
Ahh ok so split it up into two rectangles:

Rectangle one:
A=lw
A=4(12)
A=48

Rectangle two:
A=lw
A=10(2)
A=20

Add both areas up to get 68 ft squared!! :)
7 0
2 years ago
Read 2 more answers
Rayshawn has a certain amount of money if he spends $20 then he has 1/3 of the original amount how much money did Rayshawn have
erik [133]

Answer:

Rayshawn originally had $30.

Step-by-step explanation:

i) Rayshawn has a certain amount of money. Let us say this amount is $x.

ii) Rayshawn spends $20 which means that he is left with $(x - 20)

iii) it is also given that amount of money left after spending $20 is \dfrac{1}{3} of the original amount, $x, the amount remaining is \dfrac{\$x}{3}.

iv) from the information given in ii) and iii) we get

     $(x - 20) = \dfrac{\$x}{3},  Therefore we get 3x - 60 = x , therefore 2x = 60,

  Therefore x = $30. Rayshawn originally had $30.

7 0
3 years ago
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