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ss7ja [257]
3 years ago
10

2(3x +5) = 5(2x -4) -4x

Mathematics
1 answer:
pav-90 [236]3 years ago
3 0

Answer:

0= -30

Step-by-step explanation:

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Look at this graph:
zepelin [54]

Answer:

3/2

Step-by-step explanation:

slope=rise/run=30/20=3/2

5 0
3 years ago
7. Use the following figure to answer questions a-d.
kati45 [8]
B. 67
C. 43

Answer!!!!!!!!!!!!!!!!!!!
4 0
3 years ago
Just making sure my answers are right. Please show the steps clearly. Thank you so much
Artyom0805 [142]

Answer: See below

Step-by-step explanation:

A.

Let's split the integral into two parts, by the Sum Rule.

\int\limits {x-4x^3} \, dx                              [split into 2 integrals]

\int\limits {x} \, dx -\int\limits {4x^3} \, dx                      [solve integral for each part]

\frac{1}{2} x^2-x^4+C                            [Remember, we need to add C for constant]

-------------------------------------------------------------------------------------------------

B.

\int\limits {\frac{1+x}{\sqrt{x} } } \, dx                                    [expand into 2 integrals]

\int\limits {\frac{1}{\sqrt{x} } } \, dx +\int\limits {\frac{x}{\sqrt{x} } } \, dx                    [simplify second integral]

\int\limits {\frac{1}{\sqrt{x} } } \, dx +\int\limits {\sqrt{x} } \, dx                    [solve integral for each part]

2\sqrt{x} +\frac{2}{3}x^3^/^2+C

-------------------------------------------------------------------------------------------------

C.

\int\limits^4_0 {z(z^1^/^2-z^-^1^/^2)} \, dz                [distribute]

\int\limits^4_0 {z^3^/^2-z^1^/^2} \, dz                       [split into 2 integrals]

\int\limits^4_0 {z^3^/^2} \, dz -\int\limits^4_0 {z^1^/^2} \, dxz              [solve integral for each part]

\frac{64}{5} -\frac{16}{3}                                     [solve]

\frac{112}{15}

-------------------------------------------------------------------------------------------------

D. *Note: I can't put -1 for the interval, but know that the 1 on the bottom is supposed to be -1.

\int\limits^1_1 {(1+u)(1-u)} \, du                  [expand]

\int\limits^1_1 {1-u^2} \, du                              [split into 2 integrals]

\int\limits^1_1 {1} \, du-\int\limits^1_1 {u^2} \, du                      [solve integral for each part]

2-\frac{2}{3}                                      [solve]

\frac{4}{3}

4 0
3 years ago
$46 shoes; 2.9% tax.
ollegr [7]
The correct answer is 47.33 because you have to multiple 46 times 0.029 and then add 1.33 to the 46 so you get 47.33 hope this helps :)
5 0
3 years ago
Please help due today!
wolverine [178]
Sorrysorrysorrysorrysorry
7 0
3 years ago
Read 2 more answers
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