Answer:
The optimal price should be $10 which will result in maximum revenue.
Step-by-step explanation:
y = [5+ 0.5x] [ 300 - 30x]
y = 1500 - 150x + 150x - 15x^2
y = 1500 - 15x^2
x^2 = 1500 /15
x =
x = 10
2(3x +5) = 5(2x -4) -4x
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