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3 years ago

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A college has over 5,000 students, 10, percent of which are left-handed. A new lecture hall is being planned that will seat 300

students, and college officials want to be sure there are enough left-handed desks. Suppose we randomly select groups of 300 students from this college. What are the mean and standard deviation of the number of left-handed students in each group of 300? You may round your answers to the nearest tenth.

1 answer:

Rama09 [41]3 years ago

4 0

Answer:

Mean: 30 students

Standard deviation: 5.2 students

Step-by-step explanation:

Khan

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Find 5 rational numbers between -3/4 and 5/6

insens350 [35]

Answer:

1/2, 1/3, 1/4, 1/5, 1/6

Step-by-step explanation:

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3 years ago

Y=10x+2<br> y=8x+2x+2<br> How many solutions

Luba_88 [7]

Simplify y=8x+2x+2: y=10x+2
Same as equation y=10x+2
Therefore it has infinitely many solutions

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3 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

7 0

3 years ago

Which lines, if any, must be parallel based on the given information? Justify your conclusion.

77julia77 [94]

A must be parallel to b.

Proof:
∠3 = <span>∠13 (given)
</span>∠15 = <span>∠13 (vertically opposite angles are equal)
Since </span>∠13 = ∠3 and ∠13 = ∠15, ∠15 = <span>∠3

Then, a must be parallel to b (transverse line d cuts parallel lines producing converse alternate angles that are equal (ie </span>∠15 = <span>∠3))
</span>

7 0

3 years ago

Read 2 more answers

Please help me! Don't answer unless you are SURE that the answer is right, please! Will give 25 points.

Veronika [31]

the first thing to note is since one gallon= 60 miles then 1/2 gallon= 30 miles, now I know 1/2 is not an answer but it is easiest to decrease in moderate amounts. 1/2 gallon= 48 Km so we are close, and 1/2=0.5 so if we brought it down to 0.42 we would have 25.2 miles and 25.2 miles = 40.32. The question wants to know the approximate number and 40.32 is the closest we are going to get so the answer is 0.42

question 3

Answer:

80 + 65x ≤ 425

Step-by-step explanation:

First of all we know that the 425 must be greater than or equal to the other side, so the symbol to show that would be ≤. We also know that the forklift is a fixed price by the words 'each day'. And the to hire a single crew member would be $65 unless there are more crew workers, which would be multiplied with the 65.

question 4

Jimthompson5910Expert

Part A

Yes y is a function of x. Specifically the equation is y = x^5

For any given input, there is exactly one output

Notice how if x = 1 then y = x^5 = (1)^5 = 1

Notice how if x = -1 then y = x^5 = (-1)^5 = -1

Notice how if x = -2 then y = x^5 = (-2)^5 = -32

Notice how if x = 2 then y = x^5 = (2)^5 = 32

In general,

x^5 = x*x*x*x*x

there are five copies of x multiplied

A more specific example

3^5 = 3*3*3*3*3

there are five copies of '3' multiplied

=====================================================

Part B

All we do is replace x with 4 and use PEMDAS to simplify

f(x) = 2x+12

f(4) = 2(4)+12

f(4) = 8+12

f(4) = 20

The value of f(4) is 20

What does it mean? It is the total cost of renting the bowling lane for 4 hours. If you rent it for four hours, then you'll pay a total of $20.

The portion 2x = 2*4 = 8 is the variable cost which depends on how long you play. The more hours, the more the variable cost goes up

The fixed cost is 12. This is always fixed as this is the price to get in the door. If you play for 0 hours, but somehow got in the door, then you still pay $12

In total, variableCost+fixedCost = 8+12 = 20 = totalCost

5 0

3 years ago