How can I find all solutions without unit circle numbers? (ex: sinx= -3/5)
1 answer:
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Answer:
quadratic
Step-by-step explanation:
The x-values are sequential, so we can look at the y-values.
Differences from one to the next are ...
-7, -1, 5, 11, 17
And the differences of these numbers are ...
6, 6, 6, 6
When <em>second</em> differences are constant, the sequence can be produced by a <em>second</em>-degree (quadratic) polynomial.
__
Here, that polynomial is ...
y = 3x² +2x -1
The regression functions of a graphing calculator can help you find the appropriate formula.
The answer to the given question is as below:-
Polynomials:-
x³-7x²+9x-5x⁴-20
x⁵-5x⁴+4x³+2x-1
3x²-5x⁴+2x-12
Non-polynomial:-
x⁻5-5x⁻⁴+4x⁻³+2x⁻1-1
A polynomial is a mathematical equation made up of indeterminates and coefficients and involves only addition, subtraction, multiplication, and non-negative integer exponentiation of variables. The exponents of the polynomials can not be irrational.
So the table will be formed as:-
Polynomials:- Non-polynomial:-
x³-7x²+9x-5x⁴-20 x⁻5-5x⁻⁴+4x⁻³+2x⁻1-1
x⁵-5x⁴+4x³+2x-1
3x²-5x⁴+2x-12
Therefore the polynomials and non-polynomials are shown in the table above.
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Answer:
Step-by-step explanation:
Given: Hector saved twice as much money as Sam.
Ted saved $100 more than Hector.
Gina saved $50 less than Ted.
As given, lets assume the amount of money Sam has in saving be "x".
Now, finding saving of each person given.
Writing the algebric expression of each´s saving amount.
we know, Hector saved twice as much money as Sam.
∴ Hector saving=
Also, Ted saved $100 more than Hector.
∴ Ted´s saving=
Next finding Gina´s saving
As given, Gina saved $50 less than Ted.
∴ Gina´s saving=
Opening parenthesis and solving it.
⇒ Gina´s saving=
Algebric expression of Gina´s saving=
We are told that the children from a football club are put into rows in the sports hall. When put into rows of 9 children there are 2 children left over. When put into rows of 12 children there are 2 children left over.
We will find least number of children in football club by finding LCM of 9 and 12.
Multiples of 9 are: 9, 18, 27, 36, 45, 54, 63,...
Multiples of 12 are: 12, 24, 36, 48, 60, 72, 84,...
We can see that least common multiple of 9 and 12 is 36.
We are told that 2 children left over from putting them into 9 and 12 children per row. To find least number we will add 2 to 36.
Therefore, the least number of children in the football club is 38.