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Taya2010 [7]
3 years ago
6

How do you solve

exFormula1" title=" \frac{7}{8} \div \frac{1}{4} " alt=" \frac{7}{8} \div \frac{1}{4} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Soloha48 [4]3 years ago
4 0

The answer to your question is 3 1/2 as a fraction.

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The art teacher has 48 boxes of crayons.
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Mr. Valenzuela’s new bottle of shampoo contains 60 ounces of shampoo. He uses One-fourth ounce of shampoo each time he washes hi
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Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 4cm and a height of 16cm, at the ra
bearhunter [10]

Answer:

\frac{dh}{dt}=-\frac{1}{2\pi}cm/min

Step-by-step explanation:

From similar triangles, see diagram in attachment

\frac{r}{4}=\frac{h}{16}


We solve for r to obtain,


r=\frac{h}{4}


The formula for calculating the volume of a cone is

V=\frac{1}{3}\pi r^2h


We substitute the value of r=\frac{h}{4} to obtain,


V=\frac{1}{3}\pi (\frac{h}{4})^2h


This implies that,

V=\frac{1}{48}\pi h^3


We now differentiate both sides with respect to t to get,

\frac{dV}{dt}=\frac{\pi}{16}h^2 \frac{dh}{dt}


We were given that water is drained out of the tank at a rate of 2cm^3/min


This implies that \frac{dV}{dt}=-2cm^3/min.


Since we want to determine the rate at which the depth of the water is changing at the instance when the water in the tank is 8cm deep, it means h=8cm.


We substitute this values to obtain,


-2=\frac{\pi}{16}(8)^2 \frac{dh}{dt}


\Rightarrow -2=4\pi \frac{dh}{dt}


\Rightarrow -1=2\pi \frac{dh}{dt}


\frac{dh}{dt}=-\frac{1}{2\pi}






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Afina-wow [57]

Answer:

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Step-by-step explanation:

6 0
2 years ago
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