It’s D, 10.7
8 - (4.7 x (-1)) - 2 = 10.7
First aquarium dimensions:
Length = 6 m.
Width = 4 m and
Height = 2 meter.
Second aquarium dimensions:
Length = 8 m.
Width = 9 m and
Height = 3 meter.
We know formula for volume of a cuboidal box = Length*Width*Height.
Plugging values of length, width and height of first aquarium in formula of volume. We get
V1 = 6*4*2 = 48 m^3.
Plugging values of length, width and height of second aquarium in formula of volume. We get
V2 = 8*9*3 = 216 m^3.
In order to find the total cubic meters of space do the sea turtles have in their habitat, we need to add both volumes.
Therefore, Total voulme of both aquarium = V1 +V2 = 48+216 = 264 m^3.
Therefore, total 264 m^3 cubic meters of space the sea turtles have in their habitat.
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Answer:
k = 18
Step-by-step explanation:
Given that y varies inversely as x then the equation relating them is
y = 
← k is the constant of variation
To find k use the condition y = 3 when x = 6, that is
3 = 
( multiply both sides by 6 )
18 = k
The constant of variation is k = 18
