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bagirrra123 [75]

3 years ago

7

1- Caleb's family room has the dimensions shown. He needs to find the area of the room so that he knows how much carpet to buy.

Complete the area model below to find the area of the family room.

2 answers:

Rina8888 [55]3 years ago

5 0

Answer: $20\frac{11}{32}\ sq\ yd$

Step-by-step explanation:

Given: The width of the room = $3\frac{7}{8}\ yd=\frac{31}{8}\ yd$

The length of the room = $1\frac{5}{4}\ yd=\frac{21}{4}\ yd$

The area of the rectangular room= $length \times width$

⇒The area of the rectangular room= $\frac{21}{4}\times\frac{31}{8}\ sq\ yd$

⇒The area of the rectangular room= $\frac{651}{32}\ sq\ yd$

⇒The area of the rectangular room= $20\frac{11}{32}\ sq\ yd$

den301095 [7]3 years ago

4 0

8 8\12 i thnk. All i did is add but i not a whhiz and i dont know what part im supposed to be reading

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If f (1) = 5, then (1, 5) is an ordered pair of function f . <br><br> True<br> False

makkiz [27]

Answer:

true

Step-by-step explanation:

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2 years ago

A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student

umka2103 [35]

Answer:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_{M}= 69.8$ represent the mean for the age of grandmother

$\bar X_{F}= 71.6$ represent the mean for the age of grandfather

$s_{M}= 8.38$ represent the sample deviation for the age of grandmother

$s_{F}= 6.65$ represent the sample deviation for the age of grandfather

$n_M = n_F= 10$

Solution to the problem

For this case the confidence interval is given by:

$(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_M +n_F-2=10+10-2=18$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that $t_{\alpha/2}=2.101$

And replacing we got:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

5 0

3 years ago

a cyclist rode the first 32 mile portion of his workout at a constant speed. For the 28 mile cooldown portion of his workout, he

Lapatulllka [165]

The first portion is 2 and his speed during the cool down portion also 2 so I think it should be 2+2 which is 4

8 0

3 years ago

How to find the volume of the cone

gavmur [86]

Answer:

The closest measurement to the volume of hat is 84.82 in.³.

Step-by-step explanation:

Given:

The dimensions of hat are height(h) 9 inches and diameter(d) 6 inches.

Now, to find the volume of cone:

Putting the formula $\frac{1}{3}\pi r^{2}h$ .

Radius(r) is not given, finding the radius:

Radius(r)=half of the diameter(d)

$r=\frac{d}{2}$

$r=\frac{6}{2}$

$r=3$ .

Then, $\frac{1}{3}\pi r^{2}h$

= $\frac{1}{3}\times\pi \times3^{2}\times9$

= $\frac{1}{3}\times3.14\times9\times9$ ( $\pi =3.14$ )

= $\frac{1}{3} \times254.34$

= $\frac{254.34}{3}$

= $84.78$ in.³

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Sidana [21]

$1:500,000 = 8 : 8*500,000 = 8:4,000,000\\4,000,000 cm = 40 km$

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2 years ago