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lord [1]
3 years ago
12

What is the slope of a line that is perpendicular to the line whose equation is 3x+5y=4?

Mathematics
1 answer:
kap26 [50]3 years ago
8 0

Answer:

5/3 or 1.67

Step-by-step explanation:

Find the slope of the original line

3x+5y=4                Subtract 3x from both sides

5y = - 3x + 4           Divide both sides by 5

y = (-3/5)x + 4

The original line has a slope of - 3/5 or - 0.6

Find the slope of the perpendicular line

m1 * m2 = - 1

m1 = - 3/5

m2 = -1/(-3/5)

m2 = 5/3

The slope of the perpendicular line is

5/3 or 1.67

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Answer:

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Step-by-step explanation:

3(4x + 2)

you distribute the 3 to 4x and 2

12x + 6

hope this helps

5 0
3 years ago
HELP PLEASE..........
serg [7]

Answer:

19.47

Step-by-step explanation:

Use the law of sines.

sin(90)/6 = sin(x)/2

Multiply both sides by 2

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5 0
2 years ago
Which expression is equivalent to<br> (6x-9x) - (2x - 3)?
NikAS [45]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Solve the system of linear equations below.
Ugo [173]

Answer:

A. x = 2, y = 7

Step-by-step explanation:

I graphed the equations on the graph below to find the solution to the system of linear equations.

3 0
3 years ago
Help with algebra pls help
EastWind [94]

9514 1404 393

Answer:

  a. 1.48 seconds

Step-by-step explanation:

You want to find the larger value of t such that h(t) = 10.

  -16t^2 +25t +8 = 10

  16t^2 -25t +2 = 0 . . . . subtract the left side to get standard form

Using the quadratic formula, we find the values of t to be ...

  t = (-(-25) ± √((-25)^2 -4(16)(2)))/(2(16)) = (25±√497)/32

  t ≈ 0.08 or 1.48

The ball goes in the hoop about 1.48 seconds after it is thrown.

__

<em>Additional comment</em>

The quadratic formula tells us the solution to ...

  ax² +bx +c = 0

is given by ...

  x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

Here, we have a=16, b=-25, c=2. Of course, our variable is t, not x, but the relation is the same.

8 0
3 years ago
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