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andre [41]
3 years ago
5

Will the energy released in the synthesis of water equal the energy absorbed in the decomposition of water?

Chemistry
1 answer:
mariarad [96]3 years ago
6 0

Answer:

yes

Explanation:

the energy released in the synthesis of water is equal to the energy absorbed in the decomposition of water. This outcome happens because the difference in energy between the reactants and the products in both cases is equal. . It follows the law of conservation of energy.

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Determine the equilibrium constant, Keq, at 25°C for the reaction
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Explanation:

The given chemical reaction is:

2Br^- (aq) + I_2(s)  Br_2(l) + 2I^- (aq)

E^ocell=oxidation potential of anode + reduction potential of cathode\\

The relation between Eo cell and Keq is shown below:

deltaG=-RTlnK_e_q\\delta=-nFE^o cell\\=>nFE^o cell=RTlnK_e_q\\lnK_e_q=\frac{nF}{RT} E^o cell

The value of Eo cell is:

Br- undergoes oxidation and I2 undergoes reduction.

Reduction takes place at cathode.

Oxidation takes place at anode.

Hence,

E^ocell= (-1.07+0.53)V\\=-0.54V

F=96485 C/mol

n=2 mol

R=8.314 J.K-1.mol-1

T=298K

Substitute all these values in the above formula:

ln K_e_q=\frac{2mol* 96485 C/mol}{8.314 J.K^-^1.mol^-^1x298K} \\\\lnK_e_q=77.8\\K_e_q=e^7^7^.^8\\=>K_e_q=6.13x10^3^3

Answer:

Keq=6.13x10^33

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