Given:
There are given that the zeroes and degrees of the polynomial:

Explanation:
From the concept of a polynomial:
A polynomial has a as zero if and only if (x -a) is a factor of the polynomial.
Then,
From the given polynomial:

Then,

Final answer:
Hence, the polynomial is shown below:
The fourth class ends at 12:30 pm
<em><u>Solution:</u></em>
Given that Harold has 4 classes each morning
Each class is 1 hour long, and there are 10 minutes between classes
The first class is at 8 A.M
<em><u>To find: Time at which fourth class ends</u></em>
Since each is 1 hour long and 10 minutes gap between classes
First class = 8 A.M to 9 A.M
Second class = 9:10 A.M to 10 : 10 AM
Third class = 10 : 20 AM to 11 : 20 AM
Fourth class = 11 : 30 AM to 12 : 30 PM
Thus the fourth class ends at 12:30 pm
Answer:
2
Step-by-step explanation:
8 + 6 - 12 = 2