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Rom4ik [11]
3 years ago
13

A ball is placed on the ground next to a tree at the top of a hill. I need help please!!

Mathematics
1 answer:
natta225 [31]3 years ago
7 0
The ball seems to be traveling at its greatest average speed between x = 4 and x = 6 because the graph between 4 and 6 is a straight line, meaning the ball has reached the greatest possible speed.
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Find the domain and range of the function:<br> f(t)=sec[((pi)t)/4]
beks73 [17]

The domain and range of the function f(t)=sec[((pi)t)/4] are the following:

<span>Domain: All the real numbers except t = 2 + 4k, where k is an integer. </span>

Range: (-∞, -1] U [1, ∞)

I am hoping that these answers have satisfied your queries and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

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3 years ago
Natalie practices the piano 588 minutes in 2 weeks. If t represents the total time she
Ostrovityanka [42]

Answer:

T=14D

Step-by-step explanation:

I think? sorry if wrong

4 0
3 years ago
Help me please teachers trying to give me 8th grade problems
Bezzdna [24]

Answer:

x = 2

Step-by-step explanation:

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3 years ago
Read 2 more answers
Quadrilateral ABCD is dilated by a scale factor of 2 centered around (2, 2). Which statement is true about the dilation?
arsen [322]

Answer:

Option (B) is true i.e segment B'D' will run through (2,2) and will be longer than the segment BD.

Step-by-step explanation:

As the assumption quadrilateral ABCD is shown in figure a.  

First located the center of the dilation which is located at (2,2) as shown in figure b.  

The next thing we want to do is to determine the distance of the center of dilation to each of the points of quadrilateral ABCD as shown in figure b.  

Let’s just start with the distance from the center to the point A, but notice we don’t have to move up and down in y direction. So, what we have to do is to increase this by the factor 2. Because this horizontal distance is 1 i.e. the distance from dilation center (2,2) to point A, we just have to multiply by 2 which would be a distance of 2 and this point right here will be the new location of point A’ (0,2).

And the distance from the center to the point C is the horizontal distance of 2 i.e. the distance from dilation center (2,2) to point C, we just have to multiply by 2 which would be a distance of 4 and this point right here will be the new location of point C’ (6,2).

And the distance from the center to the point B is the upward vertical distance of 1 i.e. the distance from dilation center (2,2) to point B, we just have to multiply by 2 which would be a vertical distance of 2 and this point right here will be the location of point B’ (2,4).  

And similarly the distance from the center to the point D is the downward vertical distance of 1 i.e. the distance from dilation center (2,2) to point D, we just have to multiply by 2 which would be a vertical distance of 2 and this point right here will be the location of point D’ (2,0).

So, Quadrilateral A'B'C'D' is dilated by a scale factor of 2 centered around (2, 2).

Just notice in figure b that the segment B'D' will run through (2,2) and will be longer than the segment BD.

<u>So,option (B) is true</u> <u>i.e segment</u><u> </u><u>B'D' will run through (2,2) and will be longer than the segment BD.</u>

<u />

Learn more about dilation from brainly.com/question/12528454

#learnwithBrainly

3 0
3 years ago
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Suppose that Y has a gamma distribution with parameters α and β. a If a is any positive or negative value such that α + a &gt; 0
Nookie1986 [14]

Answer:

2nd option

Step-by-step explanation:

makes most sense

3 0
3 years ago
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