B, Paco won the race. Juan’s time was 15, Packs was 12, Pedros was 13. And Brads was 17.
S= 11+4t
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Cosine = adjacent/hypothenuse
Adjacent = angle between the right angle and C
Adjacent = 21
Hypothenuse = longest side
Hypothenuse = 35
Solution: 21/35
The picture in the attached figure
we know that
area of the <span>the shaded region=area of rectangle -area of a kite
area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x</span>²
area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²
area of the the shaded region=8x²-4x²-----> 4x²
the answer is 4x²
Answer:
x^87
Step-by-step explanation:
Multiplying x^22 and x^7 results in x^29.
Then we have:
(x^29)^3 = x^87
Recall that (a^b)^c = a^(bc) and that a^b*a^c = a^(b + c)