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2 years ago

Im being lazy hewp pwease :(

Mathematics

1 answer:

aalyn [17]2 years ago

5 0

Answer:

(-3,0)

Step-by-step explanation:

the vertex is where the quadratic function reaches its maximum or minimum height and as you can see on this graph the maximum height of this equation is at the (-3,0) point meaning that (-3,0) is the vertex

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-9(5-2)-111÷3 show all work

Tasya [4]

Answer:

-74

Step-by-step explanation:

First: 5-2=3

-9*3=-27

111÷3=37

Then do -27-37=-74

3 0

3 years ago

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How long will it take Mario to jog 7,560 feet if he jogs 6 feet each second?

ale4655 [162]

$7560 \div 6 = 1260$

6 0

3 years ago

What is the circumference of the base

katrin2010 [14]

43.96

Explanation:

C=2pi(r)
C=2pi(7)
C=14pi
14 x 3.14 = 43.96

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3 years ago

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Choose the correct definition of volume.

siniylev [52]

Answer:

the amount of space a 3-dimensional object takes up

Step-by-step explanation:

Of the four definition options, the first is the only only that incorporates a three dimension explanation. The others only describe a two dimension object. Units for the first would be unit^3. The other three would only be one-dimensional "units."

8 0

2 years ago

Find the inverse of ????−7 −2

Masja [62]

Answer:

$A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

Step-by-step explanation:

$A=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}$

$det\ A=-7\times 1-(-2)\times 4\\\Rightarrow det\ A=1$

$A^{-1}=\frac{1}{det\ A}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\frac{1}{1}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$\therefore A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$A.A^{-1}=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}\times \begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}\left(-7\right)\cdot \:1+\left(-2\right)\left(-4\right)&\left(-7\right)\cdot \:2+\left(-2\right)\left(-7\right)\\ 4\cdot \:1+1\cdot \left(-4\right)&4\cdot \:2+1\cdot \left(-7\right)\end{pmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}1&0\\ 0&1\end{pmatrix}$

Hence, confirmed

6 0

3 years ago