Answer:
<h2>The fourth graph, from left to right, is the correct answer.</h2>
Step-by-step explanation:
The given piecewise function is

Notice that the domain of the function specifies that, from zero to three, the function represents a decreasing (because the variable is negative) straight line. When the function is defined from 3 to infinite, the function is a constant of 5.
<em>So, the right graph must shows first a decreasing line, where the initial point is solid and the final point is empty, as the fourth fraph (from left to right), then it must show a horizontal line with an initial point solid.</em>
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Therefore, the fourth graph, from left to right, is the correct answer.
Answer:
use desmos :)) it helps
Step-by-step explanation:
Based on point P(0,16), we substitute in the parabola to find a.
16=a(0-3)^2-2 => a=(16+2)/9=2
so the parabola is
y=2(x-3)^2-2 ..........................(1)
Solve for zeroes of (1);
0=2(x-3)^2-2 => (x-3)^2=1 => x=2 or x=4
Now the line passes through (0,16), (4,0) => y,x intercepts are 16 & 4.
Using the symmetric form
x/4+y/16=1
4x+y=16 => y=16-4x