Answer:
b & b
Explanation:
Two stoves were turned off at the same time, and they both started to cool down.
The following equation gives the temperature of the first stove (in degrees Celsius) as a function of time (in minutes).
T = 180-1.55mT=180−1.55mT, equals, 180, minus, 1, point, 55, m
The graph of the temperature of the second stove (in degrees Celsius) as a function of time (in minutes) is shown below.
Which stove started at a higher temperature?
Choose 1 answer:
Choose 1 answer:
(Choice A, Incorrect)
INCORRECT
The first stove
(Choice B, Checked, Correct)
CORRECT (SELECTED)
The second stove
(Choice C, Incorrect)
INCORRECT
The stoves started at the same temperature
Which stove cooled down at a greater rate?
Choose 1 answer:
Choose 1 answer:
(Choice A, Incorrect)
INCORRECT
The first stove
(Choice B, Checked, Correct)
CORRECT (SELECTED)
The second stove
(Choice C, Incorrect)
INCORRECT
The stoves cooled down at the same rate
<h2>
B would be correct and so would be on the 2nd part</h2><h2>
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