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3 years ago

How many light years away is the sun from the middle of the Millky way

Physics

1 answer:

julsineya [31]3 years ago

4 0

Answer:

The Milky Way is about 1,000,000,000,000,000,000 km (about 100,000 light years or about 30 kpc) across. The Sun does not lie near the center of our Galaxy. It lies about 8 kpc from the center on what is known as the Orion Arm of the Milky Way

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A ray of laser light travels through air and enters an unknown material. The laser enters the material at an angle of 36 degrees

V125BC [204]

Answer:1.27

Explanation:

Given

incident angle $i=36^{\circ}$

refracted angle $r=27.5^{\circ}$

Suppose $n_2$ is the refractive index of material then using Snell's law we can write

$n_1\sin i=n_2\sin r$

where $n_1$ =refractive index of air

$1\times \sin (36)=n_2\times \sin (27.5)$

$n_2=\dfrac{0.5877}{0.4617}$

$n_2=1.27$

3 0

3 years ago

Determine the kinetic energy of a 1000 kg roller coaster car that is moving with speed of 40.0 m/s

ololo11 [35]

Answer:

KE=800,000

Explanation:

The formula for kinetic energy is KE=1/2mv^2 or Kinetic Energy= 0.5*mass*velocity^2

so 1000 is the mass and 40 is the velocity

KE=0.5*1000*40^2

KE=0.5*1,000*1,600

KE=800,000 Joules

8 0

3 years ago

What is the length a rubberband was stretched if it has a spring constant of 5700N/m and is currently holding 8600J OF POTENTIAL

lozanna [386]

Answer:

$\displaystyle \Delta x=1.74\ m$

Explanation:

<u>Elastic Potential Energy </u>

Is the energy stored in an elastic material like a spring of constant k, in which case the energy is proportional to the square of the change of length Δx and the constant k.

$\displaystyle PE = \frac{1}{2}k(\Delta x)^2$

Given a rubber band of a spring constant of k=5700 N/m that is holding potential energy of PE=8600 J, it's required to find the change of length under these conditions.

Solving for Δx:

$\displaystyle \Delta x=\swrt{\frac{2PE}{k}}$