Answer:
The radius of the circular plate is 0.774 m
Explanation:
Given;
distance between the parallel plates, d = 1.53 cm = 0.0153 m
electric field energy density between plates, = 4.41 J/m³
Potential energy of the capacitor, = 0.127 J
Energy density is given as;
where;
V is volume
Volume is given as;
V = Ad
where;
A is area
A = V / d
A = (0.0288) / (0.0153)
A = 1.882 m²
Area of circular plate is given as;
A = πr²
where;
r is the radius of the circular plate
Therefore, the radius of the circular plate is 0.774 m
Answer:
a) p = 95.66 cm, b) p = 93.13 cm
Explanation:
For this problem we use the constructor equation
where f is the focal length, p and q are the distances to the object and the image, respectively
the power of the lens is
P = 1 / f
f = 1 / P
f = 1 / 2.25
f = 0.4444 m
the distance to the object is
the distance to the image is
q = 85 -2
q = 83 cm
we must have all the magnitudes in the same units
f = 0.4444 m = 44.44 cm
we calculate
1 / p = 0.010454
p = 95.66 cm
b) if they were contact lenses
q = 85 cm
1 / p = 0.107375
p = 93.13 cm
Explanation:
Given that, two successive resonant frequencies for an open ended organ pipe (open at both ends) are 801 Hz and 890 Hz.
(a) The frequency in case of organ pipe open at both ends is given by :
L is the length of the pipe
if f = 801 Hz
.........(2)
If f = 890 Hz for (n+1)
So, .........(2)
Dividing equation (1) and (2) we get:
On solving,
n = 9
(b) The speed of sound in air, v = 343 m/s
L = 1.92 meters
Hence, this is the required solution.
Answer:
The minimum acceleration will be
Explanation:
We have given that coefficient of static friction
Frictional force is given by
Weight is given by
For train to allow the bat to remain in place
So the minimum acceleration will be
This question was apprently selected from the "Sneaky Questions" category.
The store is 3 km from his home, and he walks there with a speed of 6 km/hr. So it takes him (3 km) / (6 km/hr) = 1/2 hour to get to the store.
That's 30 minutes. So the whole part-(a.) of the question refers to only that part of the trip, and we don't care what happens once he reaches the store.
a). Over the first 30 minutes of his travel, Greg walks 3.0 km on a straight road, and he ends up 3.0 km away from where he started.
Average speed = (distance/time) = (3.0 km) / (1/2 hour) = <em>6.0 km/hr</em>
Average velocity = (displacement/time) = (3.0 km) / (1/2 hour) = <em>6.0 km/hr</em>
There's probably some more questions in part-(b.) where you'd need to use Greg's return trip to find the answers, but johnaddy210 is only asking us for part-(a.).