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kiruha [24]
3 years ago
11

ASAP! I’ll give u Brainly !

Mathematics
2 answers:
Musya8 [376]3 years ago
8 0

Answer:

(1,5)

Step-by-step explanation:

same thing as on my previous answer to another question revolving around letter F (if you're in college as your profile states I don't think you're going to do very well...)

kondor19780726 [428]3 years ago
7 0

Answer:

I'm sorry but if your struggling with this iďk what to tell you chief

  • Its (1,5)
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Roll a fair six sided die 1000 times. Out of 1000 rolls how many times an even number
Mama L [17]

Answer:

3/1000 chance

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
1. Derive the half-angle formulas from the double
lilavasa [31]

1) cos (θ / 2) = √[(1 + cos θ) / 2], sin (θ / 2) = √[(1 - cos θ) / 2], tan (θ / 2) = √[(1 - cos θ) / (1 + cos θ)]

2) (x, y) → (r · cos θ, r · sin θ), where r = √(x² + y²).

3) The point (x, y) = (2, 3) is equivalent to the point (r, θ) = (√13, 56.309°). The point (r, θ) = (4, 30°) is equivalent to the point (x, y) = (2√3, 2).

4) The <em>linear</em> function y = 5 · x - 8 is equivalent to the function r = - 8 / (sin θ - 5 · cos θ).

<h3>How to apply trigonometry on deriving formulas and transforming points</h3>

1) The following <em>trigonometric</em> formulae are used to derive the <em>half-angle</em> formulas:

sin² θ / 2 + cos² θ / 2 = 1                      (1)

cos θ = cos² (θ / 2) - sin² (θ / 2)           (2)

First, we derive the formula for the sine of a <em>half</em> angle:

cos θ = 2 · cos² (θ / 2) - 1

cos² (θ / 2) = (1 + cos θ) / 2

cos (θ / 2) = √[(1 + cos θ) / 2]

Second, we derive the formula for the cosine of a <em>half</em> angle:

cos θ = 1 - 2 · sin² (θ / 2)

2 · sin² (θ / 2) = 1 - cos θ

sin² (θ / 2) = (1 - cos θ) / 2

sin (θ / 2) = √[(1 - cos θ) / 2]

Third, we derive the formula for the tangent of a <em>half</em> angle:

tan (θ / 2) = sin (θ / 2) / cos (θ / 2)

tan (θ / 2) = √[(1 - cos θ) / (1 + cos θ)]

2) The formulae for the conversion of coordinates in <em>rectangular</em> form to <em>polar</em> form are obtained by <em>trigonometric</em> functions:

(x, y) → (r · cos θ, r · sin θ), where r = √(x² + y²).

3) Let be the point (x, y) = (2, 3), the coordinates in <em>polar</em> form are:

r = √(2² + 3²)

r = √13

θ = atan(3 / 2)

θ ≈ 56.309°

The point (x, y) = (2, 3) is equivalent to the point (r, θ) = (√13, 56.309°).

Let be the point (r, θ) = (4, 30°), the coordinates in <em>rectangular</em> form are:

(x, y) = (4 · cos 30°, 4 · sin 30°)

(x, y) = (2√3, 2)

The point (r, θ) = (4, 30°) is equivalent to the point (x, y) = (2√3, 2).

4) Let be the <em>linear</em> function y = 5 · x - 8, we proceed to use the following <em>substitution</em> formulas: x = r · cos θ, y = r · sin θ

r · sin θ = 5 · r · cos θ - 8

r · sin θ - 5 · r · cos θ = - 8

r · (sin θ - 5 · cos θ) = - 8

r = - 8 / (sin θ - 5 · cos θ)

The <em>linear</em> function y = 5 · x - 8 is equivalent to the function r = - 8 / (sin θ - 5 · cos θ).

To learn more on trigonometric expressions: brainly.com/question/14746686

#SPJ1

4 0
2 years ago
Find a third-degree polynomial function with real coefficients and with zeros at -4 and -3 5i
Charra [1.4K]

If -3+5i is a solution, then by the conjugate root theorem, -3-5i is also a solution. We find the polynomial by multiplying together the factors. If x = -4, then x + 4 is the factor. If x = -3+5i, then (x-(-3+5i)) is a factor, and so is (x-(-3-5i)). Simplifying those down gives us as the first factor as (x+3-5i) and the second as (x+3+5i). We can FOIL those 2 together to get their product, and then FOIL in x+4. FOILing the 2 complex factors together gives us x^2+3x+15ix+3x+9+15i-15ix-15i-25i^2. If we combine like terms and cross out things that cancel it's much easier than what it looks like there! It simplifies down to x^2+6x-25i^2. Since i^2 = -1, it simplifies further to x^2+6x-25(-1) and finally, to x^2+6x+25. Now we will FOIL in x+4. (x^2+6x+25)(x+4)=x^3+6x^2+25x+4x^2+24x+100. Our final simplified third degree polynomial is x^3+10x^2+49x+100

3 0
3 years ago
What is the distributive property to expand the algebraic expression.5(2f - 6g)
Gnoma [55]

Answer:

10f-30g

Step-by-step explanation:

we have:

5(2f - 6g)

we apply distributive property:

5(2f - 6g)

5*2f+5*(-6g)

finally we have:

10f-30g

7 0
3 years ago
Mrs. Cruise prepared gift baskets for her friend. She had 21 mangoes 20 apples and 14 avocados. She places the fruits in each ba
GarryVolchara [31]

Answer:

14

Step-by-step explanation:

I think. sorry if i am wrong

5 0
2 years ago
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