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The given function s/(s^2 +3s -4) is proved with the help of inverse Laplace theorem.
According to the statement
we have to find the inverse of the Laplace theorem with the help pf the given theorem in the statement.
So, For this purpose, we know that the
Laplace transformation is a transformation of a function f(x) into the function g(t) that is useful especially in reducing the solution of an ordinary linear differential equation with constant coefficients to the solution of a polynomial equation.
Now, We assume you want to find the inverse transform of
This can be written in partial fraction form as
which can be found in a table of transforms to be the transform of
There are a number of ways to determine the partial fractions. They all start with factoring the denominator.
After that, you can postulate the final form and determine the values of the coefficients that make it so.
For example:
This gives rise to two equations:
(A+B) = 1
(4B-A) = 0.
So, The given function s/(s^2 +3s -4) is proved with the help of inverse Laplace theorem.
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Question:
Use appropriate algebra and theorem 7.2.1 to find the given inverse laplace transform. (write your answer as a function of t.) ℒ−1 s s2 + 3s − 4.
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Answer & Step-by-step explanation:
In order to find the y-intercept of this equation, we must turn this equation into a slope-intercept equation. The equation for slope-intercept form is <em>y=mx+b. </em>We can do this by using these steps. Our goal is to get y by itself on one side.
6x - 2y - 9 = 0
Step 1: Add 9 on both sides of the equation.
6x - 2y = 9
Step 2: Subtract 6x on both sides of the equation. Once you subtract, make sure you put the -6x in front of 9 so we are following the rules of variables and exponents.
-2y = -6x + 9
Step 3: Divide -2 on both sides of the equation.
y = 3x -
So, the y-intercept is -