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3 years ago

An amusement park line is

Mathematics

1 answer:

Jlenok [28]3 years ago

4 0

Answer:

150 minutes, or 2 hours and 30 minutes

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Kathy has savings a hundred thousand if she invested 100,000 in a saving fund thats adds 5% each year about how much will her sa

jok3333 [9.3K]

Answer:200,000

Step-by-step explanation:

If it increases 5% every year in 20 years it will Have increased 100% therefore the number would have doubled

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3 years ago

‼️Could someone help me it’s urgent‼️

natima [27]

What’s the question?

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3 years ago

The table below lists chicks that were born to different species of birds. The second column gives the number of those chicks th

Lelu [443]

What is the probability that a Starling chick will reach adulthood?

15 out of 100 Starlings reached adulthood so there is a 15/100 probability.

15/100 reduces to 3/20 as a fraction ( 0.15 as a decimal)

If you randomly pick a blackbird or crow chick, what is the probability it will reach adulthood?

Total number of blackbirds and crows = 415 + 230 = 645

Total that reach adulthood = 50 +30 = 80

Probability of reaching adulthood = 80/645, reduces to 16/129 as a fraction

( 0.124 as a decimal)

Which species has chicks with the greatest chance of reaching adulthood?

Starlings = 15/100 = 0.15

Cardinals = 3/15 = 0.2

Pigeons = 45 /325 = 0.138

Blackbirds = 50/415 = 0.12

Crows = 30/230 = 0.13

Cardinals have the highest chance.

Which species has chicks with the least chance of reaching adulthood?

Blackbirds have the lowest chance.

8 0

3 years ago

15. Two methods are used to predict how many customers will call in for help in the next four days. The first method predicts th

Marizza181 [45]

Answer:

Method 1 has bigger forecast bias.

Step-by-step explanation:

We are given the following information in the question:

Actuals:

23, 10, 15, 19

Method 1 prediction:

23, 5, 14, 20

Residuals = Predicted - Actuals

Sum of square of errors:

$=(23-23)^2+(5-10)^2+(14-15)^2+(20-19)^2\\= 27$

Mean squared error:

$\dfrac{\text{Sum of squares}}{n} = \dfrac{27}{4} = 6.75$

Method 2 prediction:

20, 13, 14, 20

Residuals = Predicted - Actuals

Sum of square of errors:

$=(20-23)^2+(13-10)^2+(14-15)^2+(20-19)^2\\= 20$

Mean squared error:

$\dfrac{\text{Sum of squares}}{n} = \dfrac{20}{4} = 5$

Since, mean square error of method 2 is less as compared to method 1, method 1 has bigger forecast bias.

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4 years ago

FIND THE FACTORS<br> 32d4+8d

andrew11 [14]

8
d
8
d
out of
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d
4
+
8
d
32
d
4
+
8
d
.
8
d
(
4
d
3
+
1
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3 years ago

Read 2 more answers