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geniusboy [140]
3 years ago
11

1 Evaluate the expression 2a + b - 3 when a=5 and b=2. Please click on "show your work" to set up the problem and show your work

. Then, enter your answer in the box to the right. You must complete both of these steps. Evaluate the expression 2a + b - 3 when a=5 and b=2. Set up the expression and show your work.
Mathematics
2 answers:
Alexandra [31]3 years ago
8 0

Answer:

11

<em>or</em>

2(5)+2-3

Step-by-step explanation:

if a = 5 and b=2,

you add it into the expression.

2a + b -3 --> 2(5) + 2 - 3

all you have to do is replace the letters with the (given) numbers.

then, solve.

2(5) = 10

2-3= 1

10+1 =11

the answer is 11.

:)

Dmitry_Shevchenko [17]3 years ago
3 0

Answer:

The answer will be 9

Step-by-step explanation:

you should just replace the letters with numbers.

I will show you the process,

2a+b-3

=2(5)+2-3

=10+2-3

=12-3

=9

:: The answer is 9.

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kobusy [5.1K]

Answer:

3 and 7

2 and 6

4 and 8

1 and 8

Step-by-step explanation:

8 0
3 years ago
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34. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.
skad [1K]

Answer:

The linear equation for the line which passes through the points given as (-1,4) and (5,2), is written in the point-slope form as $y=\frac{1}{3} x-\frac{13}{3}$.

Step-by-step explanation:

A condition is given that a line passes through the points whose coordinates are (-1,4) and (5,2).

It is asked to find the linear equation which satisfies the given condition.

Step 1 of 3

Determine the slope of the line.

The points through which the line passes are given as (-1,4) and (5,2). Next, the formula for the slope is given as,

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute 2&4 for $y_{2}$ and $y_{1}$ respectively, and $5 \&-1$ for $x_{2}$ and $x_{1}$ respectively in the above formula. Then simplify to get the slope as follows,

m=\frac{2-4}{5-(-1)}$\\ $m=\frac{-2}{6}$\\ $m=-\frac{1}{3}$

Step 2 of 3

Write the linear equation in point-slope form.

A linear equation in point slope form is given as,

$y-y_{1}=m\left(x-x_{1}\right)$

Substitute $-\frac{1}{3}$ for m,-1 for $x_{1}$, and 4 for $y_{1}$ in the above equation and simplify using the distributive property as follows,

y-4=-\frac{1}{3}(x-(-1))$\\ $y-4=-\frac{1}{3}(x+1)$\\ $y-4=-\frac{1}{3} x-\frac{1}{3}$

Step 3 of 3

Simplify the equation further.

Add 4 on each side of the equation $y-4=\frac{1}{3} x-\frac{1}{3}$, and simplify as follows,

y-4+4=\frac{1}{3} x-\frac{1}{3}+4$\\ $y=\frac{1}{3} x-\frac{1+12}{3}$\\ $y=\frac{1}{3} x-\frac{13}{3}$

This is the required linear equation.

5 0
2 years ago
Can someone answer these questions please, i'm having trouble with them
fiasKO [112]

Answer:

1. $686.94

2. $735.03

3. $10707.55

4. $17631.94

5. $19635.72

Step-by-step explanation:

1st Question:

The interest rate is 7% for each year. This means that each year the person has to pay 7% more than the previous amount. So we need to multiply the initial amount by (0.07+1=1.07) in order to get the interest for the first year. if we want to find the second year's interests then we will have to multiply 2 (1.07)'s and so on.

in this case our function is: 600*(1.07)^t=P(t)

when t=2 P(2)=600*(1.07)^2=$686.94

2nd Question:

Function: 600*(1.07)^t=P(t)

when t=3 P(3)=600*(1.07)^3=$735.03

3rd Question:

initial value=$8500

1+0.08=1.08

Function: 8500*(1.08)^t=P(t)

t=3

P(3)=8500*(1.08)^3=$10707.55

4th Question:

initial value=$12000

1+1.08=1.08

t=5

Function: P(t)=12000*(1.08)^t

P(5)=12000*(1.08)^5=$17631.94

5th Question:

Function: 14000*(1.07)^t=P(t)

P(5)=14000*(1.07)^5

P(5)=$19635.72

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Answer:

The answer is the first option; 6^1/12

Step-by-step explanation:

We can simplify the question by using the radical rule to rewrite it as
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Then we use exponent rule which states that when we are dividing exponents of the same base, we have to subtract them. We see that the exponents are 1/3 and 1/4. So we use basic fractional division, here's the subtraction:

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Now that we have subtracted the exponents, we can write the answer as 6^1/12

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2 years ago
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