Okay lets create an eqn from that information
A first int, B second int, C third int, D fourth int.
B = A + 2
C = A + 4
D = A + 6
A is the smallest integer
B + D = 0.5 (A + C)
Now lets substitute
(A + 2) + (A + 6) = 0.5(A + (A + 4))
now lets dist
2a + 8 = 0.5(2a +4)
2a + 8 = a + 2
a + 8 = 2
a = -6
B = -6 +2
B = -4
C = -6 + 4
C = -2
D = -6 + 6
D = 0
Now using B + D = 0.5(A + C)
-4 + 0 = 0.5(-6 + (-2))
-4 = 0.5 (-8)
-4 = -4
Correct
Therefore, First integer is -6, second integer is -4, third integer is -2 and fourth integer is 0
Distance=speed times time
distance=30mi
speed=15mph
t=t
so
30=15 times t
divide both sides by 15
2=t
2 hours
Step-by-step explanation:
Bailey has 27 oz
stacie has 36 oz
tamara has 36 oz
tamara and stacie have the most water in their bottles
12v = 18+6v
move +6v to the other side
sign changes from +6v to -6v
12v-6v= 18+6v-6v
12v-6v= 18
6v= 18
divide by 6 to get v by itself
6v/6=18/6
Answer:
v= 3
Answer:
$4.75 = 4 dollars and 75 cents
Step-by-step explanation:
$1.85 for a sandwich
$1.15 for a drink
$0.65 for a bag of chips
$1.10 for two apples.
The total amount of money the student spent at lunch, in dollars and cents is:
$1.85 + $1.15 + $0.65 + $1.10
= $4.75
In words = 4 dollars and 75 cents
