How many roots does this function have? y = 8x4 - 5x3 + 2x2 - 8x + 7 no links please

Mathematics

1 answer:

Pachacha [2.7K]3 years ago

7 0

Answer:

there is no root

Step-by-step explanation:

there is no root

You might be interested in

Solve<br>-6x^2 + 6 - 2x =x

Tanzania [10]

Answer:

x1= -1-√17/4

x2= -1+√17/4

3 0

3 years ago

The length of a rectangle is 4 units greater than its width w. Write an expression for the length of the rectangle.

Shkiper50 [21]

If the length is four units greater than w, then it is equal to w+4.

6 0

3 years ago

Can someone answer this for me please.

nataly862011 [7]

I’m pretty sure the answer would be “C” I’m not sure though

4 0

3 years ago

If a= 2x - 3 and b= 2x+5<br> find the value of a+b <br> help pleaseeee i would really appreciate

Goshia [24]

Answer:

4x+2

Step-by-step explanation:

a= 2x - 3 and b= 2x+5

a+b = 2x-3 + 2x+5

Combine like terms

a+b = 4x+2

6 0

2 years ago

Read 2 more answers

Rewrite in Polar Form....<br> x^(2)+y^(2)-6y-8=0

skad [1K]

$\bf x^2+y^2-6y-8=0\qquad 
\begin{cases}
x^2+y^2=r^2\\\\
y=rsin(\theta)
\end{cases}\implies r^2-6rsin(\theta)=8
\\\\\\
\textit{now, we do some grouping}\implies [r^2-6rsin(\theta)]=8
\\\\\\\
[r^2-6rsin(\theta)+\boxed{?}^2]=8\impliedby 
\begin{array}{llll}
\textit{so we need a value there to make}\\
\textit{a perfect square trinomial}
\end{array}$

$\bf 6rsin(\theta)\iff 2\cdot r\cdot \boxed{3\cdot sin(\theta)}\impliedby \textit{so there}
\\\\\\
\textit{now, bear in mind we're just borrowing from zero, 0}
\\\\
\textit{so if we add, \underline{whatever}, we also have to subtract \underline{whatever}}$

$\bf [r^2-6rsin(\theta)\underline{+[3sin(\theta)]^2}]\quad \underline{-[3sin(\theta)]^2}=8\\\\
\left. \qquad \right.\uparrow \\
\textit{so-called "completing the square"}
\\\\\\\
[r-3sin(\theta)]^2=8+[3sin(\theta)]^2\implies [r-3sin(\theta)]^2=8+9sin^2(\theta)
\\\\\\
r-3sin(\theta)=\sqrt{8+9sin^2(\theta)}\implies r=\sqrt{8+9sin^2(\theta)}+3sin(\theta)$

3 0

3 years ago