Answer:
The angular acceleration is same at all the points in the body.
Option (D) is correct.
Explanation:
Given:
When a rigid body rotates about a fixed axis, all the points in the body have the same,
For finding which quantity is same we use pure rotational concept,

Where
angular frequency,
radius of rigid body
When a rigid body rotates about a fixed axis angular velocity of all the points in the body are same.
But the tangential speed, tangential acceleration, linear displacement, and centripetal acceleration depend on the position of the points and hence they are not the same.
Therefore, the angular acceleration is same at all the points in the body.
Answer:
a) Block 1 = 72.9kgm/s
Block 2 = 0kgm/s
b) vf = 1.31m/s
c) ∆KE = 936.36Joules
Explanation:
a) Momentum = mass× velocity
For block 1:
Momentum = 2.7×27
= 72.9kgm/s
For block 2:
Momentum = 53(0) (body is initially at rest)
= 0kgm/s
b) Using the law of conservation of momentum
m1u1+m2u2 = (m1+m2)v
m1 and m2 are the masses of the block
u1 and u2 are their initial velocity
v is the common velocity
Given m1 = 2.7kg, u1 = 27m/s, m2 = 53kg, u2 = 0m/s (body at rest)
2.7(27)+53(0) = (2.7+53)v
72.9 = 55.7v
V = 72.9/55.7
Vf = 1.31m/s
c) kinetic energy = 1/2mv²
Kinetic energy of block 1 = 1/2×2.7(27)²
= 984.15Joules
Kinetic energy of block 2 before collision = 0kgm/s
Total KE before collision = 984.15Joules
Kinetic energy after collision = 1/2(2.7+53)1.31²
= 1/2×55.7×1.31²
= 47.79Joules
∆KE = 984.15-47.79
∆KE = 936.36Joules
Answer:
Time= 1/frequency
=1/100
=0.01
Explanation:
Answer:
salt, toothpaste, and applesauce
Explanation:
All of these have minerals in them. Hope this helps! :)