3 years ago

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Physics

2 answers:

Ray Of Light [21]3 years ago

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andrey2020 [161]3 years ago

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<h3>formular kinetic energy=1/2 ×v</h3>

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2 years ago

If the range of the projectile is 4.3 m, the time-of-flight is T = 0.829 s, and air resistance is negligible, determine the foll

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Answer

given,

range of the projectile = 4.3 m

time of flight = T = 0.829 s

$v =\dfrac{d}{T}$

$v =\dfrac{4.3}{0.829}$

v = 5.19 m/s

vertical component of velocity of projectile

v_y = gt'

$v_y = 9.8 \times {\dfrac{T}{2}}$

$v_y = 9.8 \times {\dfrac{0.829}{2}}$

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a) Launch angle

$\theta = tan^{-1}(\dfrac{v_y}{v})$

$\theta = tan^{-1}(\dfrac{4.06}{5.19})$

θ = 38°

b) initial speed of projectile

$v = \sqrt{v_x^2 + v_y^2}$

$v = \sqrt{5.19^2 + 4.06^2}$

v = 6.59 m/s

c) maximum height reached by the projectile

$y_{max}=v_{avg}t'$

$y_{max}=\dfrac{1}{2}v_y\dfrac{T}{2}$

$y_{max}=\dfrac{1}{2}\times(g\dfrac{T}{2})\times\dfrac{T}{2}$

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3 years ago

A speed-time graph is a horizontal line with a y-value of 4. Which describes the objects motion?

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Light-rail passenger trains that provide transportation within and between cities are capable of modest accelerations. The magni

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During the first phase of acceleration we have:
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v = v o + a * t
13 m/s = 4 m / s + a * 8 s
a * 8 s = 9 m/s
a = 9 m/s : 8 s
a = 1.125 m/s²
The final speed:
v = ?; v o = 13 m/s; a = 1.125 m/s² ; t = 16 s
v = v o + a * t
v = 13 m/s + 1.125 m/s² * 16 s
v = 13 m/s + 18 m/s = 31 m/s

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