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Dafna1 [17]
3 years ago
7

If a wheel rotates 5 times in 90 seconds, what is the period and frequency

Physics
1 answer:
Sati [7]3 years ago
4 0

Answer:

i think it should be 18

Explanation:

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What is the car's speed at the bottom of the dip?The passengers in a roller coaster car feel 50% heavier thantheir true weight a
Rashid [163]

Answer:

v = 14 m/s

Explanation:

given,

radius of dip = 40 m

The passengers in a roller coaster car feel 50% heavier than their true weight.

Apparent weight

A = W + \dfrac{W}{2}

A =\dfrac{3W}{2}

A =\dfrac{3mg}{2}

When the car is at the bottom,  the weight will be acting downwards and the centripetal force will also be acting downward where as Normal force which is apparent weight will be acting in upward direction.

now,

N = m g + \dfrac{mv^2}{r}

\dfrac{3mg}{2} = m g + \dfrac{mv^2}{r}

\dfrac{mg}{2} = \dfrac{mv^2}{r}

v = \sqrt{\dfrac{rg}{2}}

v = \sqrt{\dfrac{40\times 9.8}{2}}

v = 14 m/s

8 0
3 years ago
How will frost on the wings of an airplane affect takeoff performance?
san4es73 [151]

Frost will disturb the smooth flow of air over the wing, unpleasantly distressing its lifting competence. In other words, this spoils the even flow of air over the wings, by this means decreasing lifting capability. Also, frost may avoid the airplane from becoming flying at normal departure speed.

8 0
3 years ago
2. The weight of a basketball player is 6 ft and 1 12 inches. Change his height to:
Elza [17]

Answer:

a feat

Explanation:

cause the mf already 7ft on the dot there is no such thing as 6 ft 12

4 0
3 years ago
In one contest at the county fair, a spring-loaded plunger launches a ball at a speed of 3.2m/s from one corner of a smooth, fla
lara31 [8.8K]

Answer:

Explanation:

Given

Speed of ball u=3.2\ m/s

Plane is inclined at an angle 20^{\circ}

To win the Game we need to hit the target at x=2.4\ m away

Launch angle of ball \theta

Motion of ball can be considered in two planes i.e. Vertical to the plane and horizontal to the plane

So Net acceleration in vertical plane is g\sin 20

Range of Projectile is given by

R=\frac{u^2\sin 2\theta }{g}

for R=2.4\ m

2.4=\frac{3.2^2\times sin 2\theta }{g\sin 20}

\sin 2\theta =\frac{2.4\times 9.8\times \sin 20}{3.2^2}

\sin 2\theta =0.7855

2\theta =51.77

\theta =25.88^{\circ}

so ball must be launched at an angle of 25.88^{\circ}

4 0
3 years ago
How much force is required to pull a spring 3.0 cm from its equilibrium position if the spring constant is 3.7 x 103 n/m?
Lubov Fominskaja [6]
Hooke's law states that for a helical spring the extension is directly proportional to the force applied provided the elastic limit is not exceeded. 
Therefore; F= ke, where k is the spring constant, F is the force and e is the extension.
k = 2700 N/m and e = 3 cm or 0.03 M
therefore, F = 2700 × 0.03
                    = 81 N
Thus, the force required will be 81 N
6 0
3 years ago
Read 2 more answers
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