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andrey2020 [161]
3 years ago
10

Jerry has a jar with 273 marbles in it. The jar can hold 1,000 marbles in all

Mathematics
1 answer:
Montano1993 [528]3 years ago
7 0

Answer:

I would say that the answer is 1000=273+m

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A tank contains 30 lb of salt dissolved in 300 gallons of water. a brine solution is pumped into the tank at a rate of 3 gal/min
sesenic [268]
A'(t)=(\text{flow rate in})(\text{inflow concentration})-(\text{flow rate out})(\text{outflow concentration})
\implies A'(t)=\dfrac{3\text{ gal}}{1\text{ min}}\cdot\left(2+\sin\dfrac t4\right)\dfrac{\text{lb}}{\text{gal}}-\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{300+(3-3)t\text{ gal}}
A'(t)+\dfrac1{100}A(t)=6+3\sin\dfrac t4

We're given that A(0)=30. Multiply both sides by the integrating factor e^{t/100}, then

e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=6e^{t/100}+3e^{t/100}\sin\dfrac t4
\left(e^{t/100}A(t)\right)'=6e^{t/100}+3e^{t/100}\sin\dfrac t4
e^{t/100}A(t)=600e^{t/100}-\dfrac{150}{313}e^{t/100}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+C
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Given that A(0)=30, we have

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so the amount of salt in the tank at time t is

A(t)\approx600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)-558.02e^{-t/100}
3 0
3 years ago
The regular price of running shoes is $89.00. They are on sale for 20% off.
noname [10]

Answer:

a. 17.80 b. 71.20

Step-by-step explanation:

I used to hate percents. Let me teach you a trick:

take the og value (89) and multiply it by the percentage (20% or 0.2). Then once you have that answer (17.80), subtract it from the og value (89-17.80). That's your answer for how much you still owe! (71.20)

any other follow up questions? Just ask :)

8 0
2 years ago
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