Jerry has a jar with 273 marbles in it. The jar can hold 1,000 marbles in all

Find the vertical asymptotes. 2x2 + 7x + 6 y = 3x2 + 10x - 8 * = [ [?], x=

Llana [10]

Answer:

$-\frac{77}{24}$

Step-by-step explanation:

1. rewrite the equation in standard form: $4\cdot \frac{3}{2}\left(y-\left(-\frac{41}{24}\right)\right)=\left(x-\left(-\frac{3}{2}\right)\right)^2$

2. find (h,k), the vertex. the vertex is $\left(h,\:k\right)=\left(-\frac{3}{2},\:-\frac{41}{24}\right)$

3. find the 'focal length' of the parabola - the focal length is the distance between the vertex and the focus. from the vertex we can see that the focal length, p, = 3/2

4. Parabola is symmetric around the y-axis and so the asymptote is a line parallel to the x-axis, a distance p from the $\left(-\frac{3}{2},\:-\frac{41}{24}\right)$ y coordinate which is at $-\frac{41}{24}\right)$ . Set up the equation:

$y=-\frac{41}{24}-p$

5. substitute and solve:

$y=-\frac{41}{24}-\frac{3}{2}$

$y = -\frac{77}{24}$

hope this helps, ask me questions if you still don't understand.

8 0

3 years ago

What is the growth (or slope) of the simplified equation??

DIA [1.3K]

Answer:i think its y+3x+8x-7

Step-by-step explanation:i dont have to explain

4 0

2 years ago

Which equations represent circles that have a diameter of 12 units and a center that lies on the y-axis

Tju [1.3M]

The equations representing the circle having a diameter of 12 units and a center lying on y-axis are x² + (y – 3)² = 36, and x² + (y + 8)² = 36, making options 1, and 5 the two choices.

In the question, we are looking for the equations of the circle having a diameter of 12 units and a center lying on y-axis.

The standard form of the equation of a circle is (x - h)² + (y - k)² + r², where (h, k) is the center of the circle, and r is its radius.

A circle having a diameter of 12 units, will have a radius of 12/2 = 6 units. Thus, r = 6.

A circle having the center on the y-axis will have a center as (0, k) as all points on the y-axis have x-coordinate 0.

Thus, the equation of the circle, with a diameter of 12 units and the center lying on the y-axis takes the form:

x² + (y - k)² = 6², or, x² + (y - k)² = 36.

From the given options, the equations x² + (y – 3)² = 36, and x² + (y + 8)² = 36, are of this form.

Thus, the equations representing the circle having a diameter of 12 units and a center lying on y-axis are x² + (y – 3)² = 36, and x² + (y + 8)² = 36, making options 1, and 5 the two choices.

Learn more about equations of circle at

brainly.com/question/16039879

#SPJ4

The provided question is incomplete. The complete question is:

"Which equations represent circles that have a diameter of 12 units and a center that lies on the y-axis? Select two options.

x² + (y – 3)² = 36
x² + (y – 5)² = 6
(x – 4)² + y² = 36
(x + 6)² + y² = 144
x² + (y + 8)² = 36."

8 0

1 year ago

Find the distance points p (3,6) and q (7,3) to the nearest tenth?

Vladimir79 [104]

<h3>Answer: 5</h3>

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One method is to plot the points P(3,6) and Q(7,3) on the same xy grid. Plot a third point R at (3,3). See the diagram below.

A right triangle forms in which we can find the legs PR = 3 and RQ = 4. The hypotenuse is found through the pythagorean theorem.

a^2+b^2=c^2

3^2+4^2 = c^2

9+16 = c^2

c^2 = 25

c = sqrt(25)

c = 5

This is the length of PQ

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Or you can use the distance formula which is effectively using the pythagorean theorem just in a slightly different format (though it may not be obvious).

$d = \text{Distance from P to Q}\\\\d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(3-7)^2+(6-3)^2}\\\\d = \sqrt{(-4)^2+(3)^2}\\\\d = \sqrt{16+9}\\\\d = \sqrt{25}\\\\d = 5\\\\$

8 0

3 years ago

Read 2 more answers

How many times will interest be added to the principal in 1 year if the interest is compounded annually?

Elena-2011 [213]

Hello!
Annually means once a year so if it is compounded annually then it is compounded only once per year, meaning interest is added to principal only 1 time per year.

Hope this helps! Any questions please just ask!! Thank you so much!!

7 0

2 years ago

Read 2 more answers