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2 years ago

Can you answer this math homework? Please!

Mathematics

1 answer:

pav-90 [236]2 years ago

7 0

Answer:

(-4.5, 4.25) The first one.

Step-by-step explanation:

Plug in -4.5 in for x and 4.25 for y in BOTH problems. When you plug them in and they both work out for BOTH problems then its the answer.

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Sixty percent of Company A’s employees are considered top performers. Fifty five percent of Company A’s employees are in a rigor

pickupchik [31]

Not exactly. there are still 40 percent of the employees that are not top performers. for all you know those 40 percent could make up the majority of the employees in the training program<span />

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3 years ago

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Plz answer fast and correctly,u will be marked brainliest

Sidana [21]

Answer:

Step-by-step explanation:

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2 years ago

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The amount of time it takes Evelyn to go grocery shopping is continuous and uniformly distributed between 20 minutes and 44 minu

vivado [14]

Answer:

85.71% probability that it takes Evelyn less than 38 minutes given that it takes less than 41 minutes for her to go grocery shopping

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

$P(X < x) = \frac{x - a}{b-a}$

Uniformly distributed between 20 minutes and 44 minutes.

This means that $a = 20, b = 44$ .

What is the probability that it takes Evelyn less than 38 minutes given that it takes less than 41 minutes for her to go grocery shopping

We know that it takes less than 41 minutes, so we can update b to 41.

$P(X < 38) = \frac{38 - 20}{41 - 20} = 0.8571$

85.71% probability that it takes Evelyn less than 38 minutes given that it takes less than 41 minutes for her to go grocery shopping

4 0

3 years ago

The length of time for one individual to be served at a cafeteria is a random variable having an exponential distribution with a

Leya [2.2K]

Answer:

a) 0.25

b) 52.76% probability that a person waits for less than 3 minutes

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \lambda e^{-\lambda x}$

In which $\lambda = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

In this question:

$m = 4$

a. Find the value of λ.

$\lambda = \frac{1}{m} = \frac{1}{4} = 0.25$

b. What is the probability that a person waits for less than 3 minutes?

$P(X \leq 3) = 1 - e^{-0.25*3} = 0.5276$

52.76% probability that a person waits for less than 3 minutes

3 0

3 years ago

Please help

mina [271]

Answer: n3 when

Step-by-step explanation: just say he fell in the water

8 0

2 years ago