Question

Jason is flying a kite and has 325 feet of kite string out. The angle of elevation between Jason’s hand and the kite string is 58˚. Jason’s hand is 3 feet above the ground. How high is the kite to the nearest tenth?
i need this asap pls

Answer 1

Answer:

The height of the kite is approximately 278.6 feet

Step-by-step explanation:

The length of Jason's Kite string, l = 325 feet

The angle of elevation of the kite string, θ = 58°

The height of Jason's hand, h = 3 feet above the ground

Therefore, we have;

The height of the kite = The vertical component of the length of the kite string + The height of Jason's hand above the ground

The height of the kite = l × sin(θ) + h

Substituting the values, we get

The height of the kite = 325 × sin(58°) + 3 ≈ 278.6 (which is obtained by rounding the answer to the nearest tenth)

The height of the kite ≈ 278.6 feet.