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horsena [70]
3 years ago
14

Jason is flying a kite and has 325 feet of kite string out. The angle of elevation between Jason’s hand and the kite string is 5

8˚. Jason’s hand is 3 feet above the ground. How high is the kite to the nearest tenth?
i need this asap pls
Mathematics
1 answer:
Sladkaya [172]3 years ago
5 0

Answer:

The height of the kite is approximately 278.6 feet

Step-by-step explanation:

The length of Jason's Kite string, l = 325 feet

The angle of elevation of the kite string, θ = 58°

The height of Jason's hand, h = 3 feet above the ground

Therefore, we have;

The height of the kite = The vertical component of the length of the kite string + The height of Jason's hand above the ground

The height of the kite = l × sin(θ) + h

Substituting the values, we get

The height of the kite = 325 × sin(58°) + 3 ≈ 278.6 (which is obtained by rounding the answer to the nearest tenth)

The height of the kite ≈ 278.6 feet.

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Does anyone know the answer? Ty
Kamila [148]

Answers:

  • JK = 29
  • LM = 29
  • KL = 10
  • MJ = 10
  • JK = LM and KL = MJ

========================================================

Explanation:

Let's plug in the given x value

  • JK = 5x+9 = 5*4+9 = 20+9 = 29
  • LM = 6x+5 = 6*4+5 = 24+5 = 29

Both JK and LM are equal to 29, so this means JK = ML

Now use the y value

  • KL = 2y-6 = 2*8-6 = 16-6 = 10
  • MJ = y+2 = 8+2 = 10

Both JM and KL are equal to 10, so JM = KL

These facts are sufficient to prove we have a parallelogram.

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2 years ago
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find the indicated limit, if it exists. limit of f of x as x approaches 8 where f of x equals x plus 10 when x is less than 8 an
ratelena [41]
f(x)= \left \{ {{x + 10;  \  \  \ x \ \textless \  8} \atop {10-x;  \  \  \ x  \geq 8}} \right. \\  \\ lim_{x \rightarrow 8} (f(x))^-=8+10=18 \\ lim_{x \rightarrow 8} (f(x))^+=10-8=2  \\ Since \ lim_{x \rightarrow 8} (f(x))^- \neq lim_{x \rightarrow 8} (f(x))^+
Therefore, the limit does not exist.
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The resistance, R, to electricity of a cylindrical-shaped wire is given by the equation R=pL/(pi)d^2 where p represents the resi
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D.) The resistance approaches infinity.

Step-by-step explanation:


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Consider the following time series: t12345 6 11 9 14 15 a. Construct a time series plot. What type of pattern exists in the data
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Answer:

Kindly check explanation and attached picture

Step-by-step explanation:

Given the time-series data:

Time (x) : 1 - - 2 - - 3 - - - 4 - - - 5

Data (yt) :6 - - 11 - - 9 - - 14 - - 15

The pattern which exists within the data is a linear pattern which could be inferred through the observable decrement and Incremental change in the y values at a steady or constant rate with time. The second attachment shows the linear trend line of the data.

4 0
3 years ago
a missile is launched from the ground. its height, h(x), can be represented by a quadratic function in terms of time, x, in seco
fomenos

Answer:

The height of the missile in the air  after 11 seconds is 330 feet.

Step-by-step explanation:

The standard form for the quadratic function f(x)= ax^2 + bx + c, which is the function of the parabola model.

We are given two points.

(1, 130) and (2, 240)

Here the first coordinate represents the x (time) and the second coordinate represents h(x), which is height.

Now plug these two coordinates and find the two equations.

(1, 130), the equation is

130 = a.(1)^2 + b(1) + c, where "c" is the initial height. Which is equal to zero.

Therefore, we get

130 = a + b + 0

a + b = 130 -------(1)

Now let's form the second equation using the coordinate (2, 240)

240 = a(2)^2 + b(2) + 0

240 = 4a + 2b -------------(2)

Now let's solve the equations (1) and (2) and find the value of "a" and "b"

a + b = 130 can be written as a = 130 - b

Here we can use the substitution method.

Now plug in a = 130 - b in the second equation, we get

240 = 4(130 - b) + 2b

240 = 520 - 4b + 2b

240 = 520 - 2b

2b = 520 - 240

2b = 280

Dividing both sides by 2, we get

b = 140

Now plug in b = 140 in a = 130 -b and find the value of a

a = 130 - 140

a = -10

Now we got a = -10 and b = 140.

We plug in a = -10 and b = 140 in the general form, we gety

h(x) = -10x^2 + 140x + c

Where c is the initial height, which is equal to 0.

h(x) = -10x^2 + 140x

Now plug in x = 11 seconds and find the height.

h(11) = -10(11)^2 + 140 (11)

= -10 (121) + 1540

= - 1210 + 1540

h(11) = 330 feet,

Therefore, the height of the missile in the air  after 11 seconds is 330 feet.

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